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Gnoma [55]
2 years ago
12

If we changed the 3 to a 0 in the equation, what would happen to the graph?

Mathematics
1 answer:
Rus_ich [418]2 years ago
7 0

A function assigns the values. The function will move down by 3 units.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

The graph of the function is given below. Now if 3 is replaced by a 0, then the y-intercept of the function will become zero while keeping the slope the same. Therefore, the function will move down by 3 units.

Learn more about Function:

brainly.com/question/5245372

#SPJ1

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Evaluate 4c + 8 when c = 2
Wittaler [7]

Answer:

16

Step-by-step explanation:

4c + 8

Replace 'c' with 2 and evaluate:

4(2) + 8

8 + 8

16

Hope this helps.

8 0
3 years ago
Read 2 more answers
Give the dimensions of the small prisms that can be used to pack the larger prism
Neporo4naja [7]
Okay we'll go through all the steps. Ready?

4 0
3 years ago
Multiply. Write the product in simplest form. 6/7 × 6/11 steps and how to. and work
Triss [41]

multiply 6 x 6 to get 36 and 7 x 11 to get 77.

6/7 x 6/11 = 36/77

5 0
3 years ago
12а + 7x - За – 2х what's the answer<br>​
Troyanec [42]
9a-5x

step by step explanation:

you can only add and subtract numbers that have the same variables.

12a and 3a are related because there variable is both a.

when u subtract 12a-3a you get the answer of 9a using subtraction.

7x and -2x are the second pair of related terms because they also have the same variable (x)

7x-2x is 5x using subtraction.

put the expression together:

9a-5x

hope this helps!

give me brainliest if it did plz
8 0
3 years ago
EX 6.1 How many iterations will the following for loops execute? for (int i = 0; i &lt; 20; i+ +) { } for (int i = 1; i &lt;= 20
Romashka-Z-Leto [24]

Answer:

20, 20, 15, 20, 10, and 5 iterations respectively

Step-by-step explanation:

The loop "for (int i = 0; i < 20; i+ +)" starts at i=0 and increases the counter i by 1 at the end of each iteration. The counter must be less than 20, so the values of i in the loop are 0,1,2,3,...,19. These are 20 values, and thus the code iterated 20 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and increases the counter i by 1 at the end of each iteration. The counter can't exceed 20, so the values of i in the loop are 1,2,3,4,...,20. These are 20 values, and thus the code iterated 20 times.

Similarly, in "for (int i = 5; i < 20; i+ +)" i takes the 15 values are 5,6,7,...,19. Hence, the code iterated 15 times.

The loop "for (int i = 20; i > 0; i- -)" starts at i=20 and decreases the counter i by 1 at the end of each iteration, so the values of i in the loop are 20,19,18,...,1. These are 20 values, then we have 20 iterations.

The loop "for (int i = 1; i < 20; i = i + 2)" starts at i=1 and increases the counter i by 2 at the end of each iteration. The values of i in the loop are 1,3,5,7,...,19. These are 10 values, and thus the code iterated 10 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and multiplies the counter i by 2 at the end of each iteration, so the values of i in the loop are 1,2,4,8,16. Then we have 5 iterations.

6 0
3 years ago
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