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Gnoma [55]
1 year ago
12

If we changed the 3 to a 0 in the equation, what would happen to the graph?

Mathematics
1 answer:
Rus_ich [418]1 year ago
7 0

A function assigns the values. The function will move down by 3 units.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

The graph of the function is given below. Now if 3 is replaced by a 0, then the y-intercept of the function will become zero while keeping the slope the same. Therefore, the function will move down by 3 units.

Learn more about Function:

brainly.com/question/5245372

#SPJ1

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Select the correct answer.
sergeinik [125]

Answer:

C. 1:27

Step-by-step explanation:

a²/b²=1/9 => a=1 and b=3

a³/b³=1³/3³=1/27

C. 1:27

8 0
3 years ago
Read 2 more answers
What is the period? Please show work.
Sophie [7]

Answer:

2πl/3

Step-by-step explanation:

find properties of the trigonometric function:

period 2π/3

3 0
2 years ago
What number gives a result of −5 when 9 is subtracted from the quotient of the number and 6?
My name is Ann [436]

Answer:

25

Step-by-step explanation:

If it gives a result of -4 then our equation will have .... = -4

 

If we subtract 9 from the quotient of a number and 5 we have  x/5 - 9

 

Our equation is:

 

x/5 - 9 = -4     add 9 to both sides

x/5 = -4 + 9

x/5 = 5           multiply both sides by 5

x = 5(5)

x = 25

Check:  25/5 - 9 = 5-9 = -4

           Answer checks as correct from information given

 

8 0
3 years ago
Solve for x. Show each step of the solution.<br> Show each step when solving for x.
andrew-mc [135]

-3x(4-6x) < x+5

-12x+18x² < x+5

-13x+18x² < 5

18x²-13x-5<0.

4 0
3 years ago
Find the equation of an exponential function in the form y = ab^x, given the points (0, 3) and (2, 108/25). Please simplify your
lilavasa [31]

We have the equation:

y=a\cdot b^x

We know two points and we will use them to calculate the parameters a and b.

The point (0,3) will let us know a, as b^0=1.

\begin{gathered} y=a\cdot b^x \\ 3=a\cdot b^0=a \\ a=3 \end{gathered}

Now, we use the point (2, 108/25) to calcualte b:

\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}

Then, we can write the equation as:

y=3\cdot(\frac{6}{5})^x

5 0
1 year ago
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