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Law Incorporation [45]
3 years ago
5

Esther is pregnant and preparing for the birth of her first baby. In college, she ran up a large credit card bill and is still t

rying to pay it off while still charging new items.
What would you recommend she do as soon as possible?


use money she planned to spend on her medical bills to pay her credit card

use credit cards to pay for all expenses associated with having a baby

keep her spending habits the same

stop using all credit cards at once
Mathematics
1 answer:
Yuki888 [10]3 years ago
5 0

Answer:use money she planned to spend on her medical bills to pay her credit card

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Answer:

86 is the mean and the median is 85

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2.) The equation yˆ=−8.74x2+50.57x+39.02 models the number of customers in a store x hours after opening.
Artemon [7]

Answer:

2. The correct option is;

D. 112

3. The predicted number of cellular subscription per 100 people in Australia in 2030 is 217 subscriptions

4. The equation of the quadratic regression curve is y = x² - 6×x + 4.1

5. The closest option is;

C. 4191

Step-by-step explanation:

2. The equation for the number of customers in a store is presented as follows;

y = -8.74·x² + 50.57·x + 39.02

Where:

x = Number of hours after opening

∴ When x = 3 hours

y = -8.74×3² + 50.57×3 + 39.02 = 112.07 ≈ 112 people

The correct option is D. 112

3. The expression of the regression equation is presented as follows

y = -0.107·x² + 9.008·x +28.851

Where:

x = Number of years since 1990, hence

When x = 2030 - 1990 = 40 Years

Hence, the predicted number of cellular subscriptions per  people in 2030 is presented as follows;

y = -0.107×40² + 9.008×40 +28.851 = 217.971 Subscribers

To round down to the nearest whole number as y = 217 subscribers

4. The general form of a quadratic equation is presented as follows;

y = a·x² + b·x + c

When x = 0, y = 4.1, therefore;

4.1 =  a×0² + b×0 + c = c

∴ c = 4.1

When x = 1, y = -0.9, therefore;

-0.9 =  a×(1)² + b×1 + c = c

-0.9 =  a + b + 4.1

∴ a + b = -0.9 - 4.1 = -5.0

When x = 2, y = -3.9, therefore;

-3.9 =  a×(2)² + b×2 + c = c

-3.9 =  4·a + 2·b + 4.1

∴ 4·a + 2·b = -3.9 - 4.1 = -8.0

Thus we have two equations;

a + b = -5.0..................(1) and

4·a + 2·b = -8.0 ..........(2)

Multiply equation (1) by 2 and subtract it from equation (2), we have

4·a + 2·b - 2×(a + b) = *8.0 - (2 ×-5.0)

∴ 2·a = 2

a = 1

From equation (1,)  we have;

a + b = -5.0..................(1)

Therefore, where a = 1 we have, 1 + b = -5.0

Hence, b = -5.0  - 1 = -6.0

Therefore, the equation of the quadratic regression curve is presented as follows;

y = x² - 6×x + 4.1

5. The quadratic regression equation is found as follows;

The general form of a quadratic equation is presented as follows;

y = a·x² + b·x + c

When x = 55, y = 3650, therefore;

3650=  a×55² + b×55+ c................(1)

When x = 65, y = 4569, therefore;

4569=  a×65² + b×65+ c ...........(2)

When x = 75, y = 6147, therefore;

6147=  a×75² + b×75+ c............(3)

Solving the system of equation;

3650=  a×55² + b×55+ c................(1)

4569=  a×65² + b×65+ c ...........(2)

6147=  a×75² + b×75+ c............(3)

Subtracting equation (1) from (2), we obtain;

4569 - 3650 =  a×65² + b×65 + c - (a×55² + b×55 + c)

919 = 1200·a + 10·b...........(4)

Subtracting equation (2) from (3), we obtain;

6147 - 4569 =  a×75² + b×75 + c - (a×65² + b×65+ c)

Which gives;

1578 = 1400·a + 10·b...........(5)

Subtracting equation (4) from equation (3), we obtain;

1578 - 919 = 1400·a + 10·b - (1200·a + 10·b)

659 = 200·a

a = 659/200= 3.295

Substituting the value of a in equation (4), we have;

919 = 1200×3.295 + 10·b = 3954 + 10·b

∴ 10·b = 919 -3954 = -3035

b = -3035/10 = -303.5

Substituting the value of a and b in equation (1), we have;

3650 =  (3.295)×55² + (-303.5)×55+ c

3650 = -6725.125 + c

∴ c = 3650 - (- 6725.125)= 10375.125

Therefore, the quadratic regression equation is presented as follows;

y = 3.295·x - 303.5·b +10375.125

Hence, in 1961, x = 1961 - 1900 = 61, we have

y = 3.295×61² - 303.5×61 10375.125= 4122.32

Therefore, the closest option is C. 4191.

7 0
3 years ago
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