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garik1379 [7]
3 years ago
14

40% de cuanto son 32?

Mathematics
2 answers:
Alona [7]3 years ago
6 0

80

I don't know this language, but I am typing in English.

Go to GOOGLE TRANSLATE!

OlgaM077 [116]3 years ago
4 0

Do not speak Spanish

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Which box is greater,a 1.5 lb box of raisins or a 650 gram box of raisins
ladessa [460]

First you would have to either make everything pounds or everything grams. If you chance everything into grams it would be about 680, so the 1.5 pound box of raisens would be more. 
4 0
3 years ago
55 is 40% of what number
Oxana [17]
It is important to do the calculations very carefully. Otherwise there is nothing complicated about this problem.
Let us assume the unknown number = x
Then
40x/100 = 55
40x = 55 * 100
40x = 5500
x = 5500/40
  = 550/4
  = 137.5
So 55 is 40% of 137.50. I hope the procedure is clear to you and in future you can solve such problems on your own without requiring any help from outside.This is the simplest way of solving such problems.



5 0
3 years ago
Read 2 more answers
The mean of a normal probability distribution is 500 and the standard deviation is 10. about 95 percent of the observations lie
PIT_PIT [208]

Answer:

So about 95 percent of the observations lie between 480 and 520.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

The mean is 500 and the standard deviation is 10.

About 95 percent of the observations lie between what two values?

From the Empirical Rule, this is from 500 - 2*10 = 480 to 500 + 2*10 = 520.

So about 95 percent of the observations lie between 480 and 520.

5 0
3 years ago
A) Determine which amounts of postage can be formed using just 3-cent and 10-cent stamps.
RUDIKE [14]

wait i will take screen shot please bran-list

8 0
3 years ago
An aptitude test is designed to measure leadership abilities of the test subjects. Suppose that the scores on the test are norma
Komok [63]

Using the normal distribution, it is found that 0.0329 = 3.29% of the population are considered to be potential leaders.

In a <em>normal distribution</em> with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 550, hence \mu = 550.
  • The standard deviation is of 125, hence \sigma = 125.

The proportion of the population considered to be potential leaders is <u>1 subtracted by the p-value of Z when X = 780</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{780 - 550}{125}

Z = 1.84

Z = 1.84 has a p-value of 0.9671.

1 - 0.9671 = 0.0329

0.0329 = 3.29% of the population are considered to be potential leaders.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

8 0
2 years ago
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