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NeTakaya
3 years ago
8

How many times can 15 go into 96

Mathematics
1 answer:
Naya [18.7K]3 years ago
6 0
The answer is not a whole number depending on what the question allows as an answer it could be 6 remainder 6 or 6.4 as a decimal.
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Triangle ABC is transformed to obtain triangle A′B′C′:
GaryK [48]

Answer:

327

Step-by-step explanation:

7 0
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What is the mean in these numbers 50 60 80 90 100
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76

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8 0
2 years ago
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What value of n makes the equation true?
Naddik [55]

Answer:

n = 5.2.

Step-by-step explanation:

-20.8 = -4n

We divide both sides of the equation by -4:

-20.8 / -4 = -4n/-4

5.2 = n  (answer).

4 0
3 years ago
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Un chip tiene un espesor de 0,12 mm y un atomo de cobre mide 0,00000000133 m.¿cuantos atomos se necesita para alinearlos en el e
aleksandr82 [10.1K]

Answer:

El espesor de un chip es de 0.12mm

Y el diámetro de un átomo de cobre, mide aprox:

0.00000000133 m

Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm

Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm

Primero, escribamos ambos valores en las mismas unidades, sabiendo que:

1m = 1000mm

Podemos reescribir:

0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm

Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm

Esto sera igual al cociente entre 0.12mm y  0.00000133mm, esto es:

N = (0.12mm)/(0.00000133mm) = 90,225.6

Redondeamos al próximo número entero:

N = 90,226

Esa es la cantidad de átomos que se necesitan.

7 0
3 years ago
-17+ 1/4 x + 1/4 x + 31 = 24
wlad13 [49]
<h2><u>Answer:</u></h2><h2><u></u>\boxed{x=20}<u></u></h2><h2><u></u></h2><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) Combine like terms:</h3>
  • \frac{1}{4}x+\frac{1}{4}x=\frac{1}{2}x

<em>  - We do this because we need 1 Number/Variable left over. </em>

<u>Equation at the end of Step 1:</u>

  • <u />-17+\frac{1}{2}x+31=24<u />

<em />

<h3>2.) Add −17 and 31:</h3>
  • -17+31=14

<em>  - We do this because we can only have 1 number on each side of the equals. (This doesn't count towards the number connected to the variable.)</em>

<u>Equation at the end of Step 2:</u>

  • <u />14+\frac{1}{2}x=24<u />

<h3>3.) Subtract 14 from both sides:</h3>
  • 14-14= Cancels Out
  • 24-14=10

<em>  - We do this because now we just need the 1 variable and the 1 number on opposite sides of the equal.</em>

<u>Equation at the end of Step 3:</u>

  • <u />\frac{1}{2}x=10<u />

<h3>4.) Multiply both sides by 2:</h3>
  • <em />\frac{1}{2}x<em> </em>× 2=x<em />
  • <em />10<em> </em>× 2=20

<em>  - We multiply by 2 since we have a fraction. In this case the reciprocal is 2 meaning we multiply by 2. </em>

<em></em>

______________________________

4 0
3 years ago
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