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Yakvenalex [24]
4 years ago
11

Problem page a - tall building casts a shadow. the distance from the top of the building to the tip of the shadow is . find the

length of the shadow. if necessary, round your answer to the nearest tenth.
Mathematics
1 answer:
Nimfa-mama [501]4 years ago
4 0
Need to know numbers to solve.
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What is an approximate equation passing through the lines (2,4) and (3,7)
babymother [125]

First, let's find what m is, the slope of the line...

m= y2-y1/x2-x1

m=7-4/3-2 You end up with 3/1 or 3 as your slope.

so far you have... y=3x+b

<span>Take (2,4). y=mx+b or 4=3*2+b, solving for b: b=4-(3)(2). b=-2.</span>

So your final equation is...

<span>y = 3x-2</span>

4 0
4 years ago
To increase sales, an online clothing store began giving a 50% off coupon to random customers. Customers didn't know whether the
ludmilkaskok [199]

To increase sales, an online clothing store began giving a 50% off coupon to random customers Six customers each made purchases from the website the binomial random variable and  mean and standard deviation of X  is mathematically given as

X ~ Bin(n = 6, p = 0.2)

x= 0.9798

<h3>What is a binomial random variable?</h3>

Generally, the equation for is mathematically given as

P(coupon) = 1/5

P(coupon)= 0.2

the binomial distribution

X ~ Bin(n = 6, p = 0.2)

Therefore, The mean and standard deviation of X

пВ = np \\np= 6* 0.2 = 1.2\\

x=\sqrt{ np(1 - p)} \\ x=\sqrt{ 6 * 0.2 + (1 -0.2)} \\

x= 0.9798

In conclusion, mean and standard deviation of X

x= 0.9798

Read more about binomial

brainly.com/question/3560614

#SPJ1

6 0
2 years ago
The number of bacteria present in a culture after t minutes is given as where k is a constant. if there are 8520 bacteria presen
andrew-mc [135]
Given that the situation has been modeled by the formula:
B=1000e^(kt)
given that B=8520 after t=15 min
then the value of k will be solved as follows:
plugging in the values in the formula and solving for k
8520=1000e^(15k)
8.52=e^(15k)
solving for k
15k=ln(8.52)
hence
k=ln(8.52)/15
k=0.1428
k=0.143
8 0
3 years ago
Read 2 more answers
500 cats were chosen. 52% of the cats liked to sleep inside the house. Fish was the favorite dish of 25% of those cats, while 62
Alex777 [14]
You would need to take 500 * .52 = 260 next take 260 * .25 to find how many cats like fish which equals 65, the probability that it likes fish and it sleeps inside can be found by taking .52 * .25 = .13 so there would be a 13% chance of picking a cat that sleeps indoors and likes fish, 435 cats dont like fish found by taking 500-65=435 and finally to find how many cats sleep outside take 500-260=240 then take 240 * .625 = 150 then 240-150 = 90 so 90 cats like to sleep outside and like fish thats it!=) Hope this helps!
3 0
3 years ago
Read 2 more answers
The answers are here I just need the work please!!
Flura [38]

the answer 236e

plzzzzzzzzzzz f u  ck off


4 0
4 years ago
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