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3 years ago

The product of a number w and 737

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

7 0

The product (multiplication) of a number w and 737.

737w

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Jeff mixed together 2 cups of grapefruit juice and 5 3/4 cups of lemon-lime soda to make punch. How many cups of punch did Jeff

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Jeff made 7 cups . Hope I helped

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3 years ago

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Find the slope of the line that passes through the points (-8, 3) and (7, 3)

taurus [48]

Answer:

slope : 1/15

Step-by-step explanation:

slope = change in y / change in x

change in y = 1 / change in x = 15

therefore, 1/15 = slope

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3 years ago

Luke buys $14.35 worth of gasoline for his car. If the gas station $1.409 per gallon, how many gallons did he get? Round to the

iragen [17]

Answer:

10.2 gallons

Step-by-step explanation:

Luke buys $14.35 worth of gasoline for his car

The gas station sells at $1.409 per liter

Therefore the number of gallons that luke buys can be calculated as follows

= 14.35/1.409

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2 years ago

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What does it mean to find the sin, cos, and tan of the angle θ?

djyliett [7]

Sin means to divide the opposite side measure by the hypotenuse. Cos is equal to the adjacent side value divided by the hypotenuse. Tan is equal to the opposite value divided by the adjacent. To remember this, I use the abbreviation SOHCAHTOA. SOH for Sin is Opposite over Hypotenuse, and so on.

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3 years ago

A professor has recorded exam grades for 10 students in his class, but one of the grades is no longer readable. If the mean sco

Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

$\frac{R+x}{10} =80$

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

$\frac{R}{9} = 85\\$ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.

Based on the equation above, we can find what "R" is by multiplying both sides by 9:

$\frac{R}{9} = 85\\R=85*9= 765$

Therefore we can now use this value of R in the very first equation we created, and solve for "x":

$\frac{R+x}{10} =80\\\frac{765+x}{10} =80\\765+x=80*10=800\\765+x=800\\x=800-765=35$

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2 years ago