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2 years ago

Please help me with maths. it's a standard form topic

Mathematics

1 answer:

dimulka [17.4K]2 years ago

7 0

Answer:

Bacteria A has diameter size of 1 micrometer = 1 × 10⁻⁶ m

a) B is 1× 10⁻³ size of A:

1 × 10⁻⁶ * 1 × 10⁻³ = 1 × 10⁻⁹ m

b) 1 nanometer = 1 × 10⁻⁹ m

And bacteria B diameter size is equal to 1 nanometer

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Pls anwser this :) it’s math (5)

sleet_krkn [62]

Answer:

The answer is 4

Step-by-step explanation:

2/3 x 6= 4

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3 years ago

Write an expression equivalent to -12/27 (it is a fraction)

rusak2 [61]

-4/9 is simplified of -12/27

6 0

2 years ago

Find ratio equal to 12:7

Dmitry [639]

12:7
12(2):7(2)
24:14

12:7 = 24:14
I hoped I helped(:

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3 years ago

Read 2 more answers

PLZ HELP!!! Use limits to evaluate the integral.

Marrrta [24]

Split up the interval [0, 2] into n equally spaced subintervals:

$\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]$

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

$r_i=\dfrac{2i}n$

where $1\le i\le n$ . Each interval has length $\Delta x_i=\frac{2-0}n=\frac2n$ .

At these sampling points, the function takes on values of

$f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}$

We approximate the integral with the Riemann sum:

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3$

Recall that

$\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4$

so that the sum reduces to

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}$

Take the limit as n approaches infinity, and the Riemann sum converges to the value of the integral:

$\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}$

Just to check:

$\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28$

4 0

2 years ago

Which is greater 0.205 or 205/1000

Burka [1]

Neither...

205/1000 equals .205

So they are both the same.

Hope this helps -J

8 0

2 years ago