Answer:
2 1/4 times
Step-by-step explanation:
A builder was building a fence. In the moring he worked 2/5 of an hour. In the afternoon he wirked for 9/10 of an hour. how many times as long in the morning did he work in the afternoon
Note that:
1 hour = 60 minutes
In the moring he worked 2/5 of an hour.
= 2/5 × 60 minutes
= 24 minutes
In the afternoon he worked for 9/10 of an hour
Hence:
9/10 × 60 minutes
= 54 minutes
How many times as long in the morning did he work in the afternoon?
This is calculated as number of minutes worked in the afternoon ÷ Number of minutes worked in the morning
= 54 minutes/24 minutes
= 2 6/24
= 2 1/4 times
Answer:
The middle terms do not take into ........
Answer:
125 and 185
Step-by-step explanation:
first u have to use the table values and put them in the linear equation.
so you have in first: w= 7, so: h= 20.7-15-->h=125
and in the last: w=10, so h=20.10-15-->h=185
Here,
In Right angle triangle,
base = 12 m
height = 8 m
Now,
◇ Area = 1/2*b*h
= 1/2*12*8
= 48 m^2
In semicircle,
radius = 4 m
Then,
◇Area" = 1/2*22/7*r^
= 1/2*22/7*4*4
= 25.14m^2
Again,
◆Total Area = Right triangle + semicircle
= (48+25.14) m^2
= 73.14 m^2
This is right answer...
I hope you understand...
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