Answer:
Step-by-step explanation:
First, we swap x and y. Then, we solve for y in the new equation.
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Notice that the pattern is "previous term plus 2". This is an arithmetic sequence where the difference (d) equals +2
= a₁ + d(n - 1) ; where a₁ is the first term, d is the difference, and n is the term.
f(n) = 1 + 2(n - 1)
f(n) = 1 + 2n - 2
f(n) = 2n - 1
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f(10) = 2(10) - 1
f(10) = 20 - 1
f(10) = 19
Answer:
19 691 miles
Step-by-step explanation:
Last year, it drove 100%, which is 196,910. This year, it drove 90% lesser, so it actually only drove: 100% - 90% = 10%.
10% as a fraction is .
Distance travelled this year = × 196 910
= 19 691 miles
Answer:
a)
A(t) = 1,000,000 + 10,000,000t
B(t)= 0.01 +0.02t
b) No.
Step-by-step explanation:
a)<u> Penalty A:</u> 1 million dollars on August 2 and the fine increases by 10 million dollars each day thereafter.
If t represents the number of days after August 2,
A(t) = 1,000,000 + 10,000,000t
<u>Penalty B</u>: 1 cent on August 2 and the fine doubles each day thereafter.
A(t) = 0.01 + 2t(0.01) = 0.01 + 0.02t
b) Assuming your formulas in part (a) hold for t≥0, is there a time such that the fines incurred under both penalties are equal?
To solve this, we would have to equal both formulas and solve for t.
By taking a look at this equation, we see that when we solve for t, t will be a negative number. Since the formulas are valid for t≥0, we can conclude that there won't be a time such that the fines are equal.