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3 years ago

Are the linear expression 10x+15 and 5(2x+3) equivalency?

Mathematics

2 answers:

dangina [55]3 years ago

8 0

Answer:

They are equivalent

Step2247 [10]3 years ago

3 0

Answer:

The expressions are equivalent

Step-by-step explanation:

5(2x+3)

Distribute the 5

5*2x + 5*3

10x +15

That is equal to 10x+15

The expressions are equivalent

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Daniel [21]

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3 years ago

The ratio of the measures of the sides of a triangle is

Nezavi [6.7K]

Answer:

The length is 120 yards

Step-by-step explanation:

Here, we want to find the length of the longest side

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So the length will be;

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3 years ago

A museum groundskeeper is creating a semicircular statuary garden with a diameter of 36 feet. There will

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Answer:

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Step-by-step explanation:

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3 years ago

A bag of 12 apples is most likely to weight

tamaranim1 [39]

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3 years ago

Read 2 more answers

70 POINTS!!!!!!!!!! Given: E, F, Q, D∈k(O),O ∈ ED, m∠DFQ = 10°, measure of arc EF = 28° Find: Angles of △EFQ

Likurg_2 [28]

Answer:

The measures of angles of triangle EFQ are

1) $m\angle EFQ=100\°$

2) $m\angle FEQ=66\°$

3) $m\angle EQF=14\°$

Step-by-step explanation:

step 1

Find the measure of arc QD

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle DFQ=\frac{1}{2}(arc\ QD)$

substitute the given value

$10\°=\frac{1}{2}(arc\ QD)$

$20\°=(arc\ QD)$

$arc\ QD=20\°$

step 2

Find the measure of arc FQ

we know that

$arc\ QD+arc\ FQ+arc\ EF=180\°$ ---> because ED is a diameter (the diameter divide the circle into two equal parts)

substitute the given values

$20\°+arc\ FQ+28\°=180\°$

$arc\ FQ=180\°-48\°=132\°$

step 3

Find the measure of angle EFQ

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle EFQ=\frac{1}{2}(arc\ QD+arc\ ED)$

substitute the given value

$m\angle EFQ=\frac{1}{2}(20\°+180\°)=100\°$

step 4

Find the measure of angle FEQ

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle FEQ=\frac{1}{2}(arc\ FQ)$

substitute the given value

$m\angle FEQ=\frac{1}{2}(132\°)=66\°$

step 5

Find the measure of angle EQF

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle EQF=\frac{1}{2}(arc\ EF)$

substitute the given value

$m\angle EQF=\frac{1}{2}(28\°)=14\°$

5 0

4 years ago