What is the answer to 2 4/5+5 2/3 in simplified form

Which expression is equivalent to (x3 · x2)5? x10

marysya [2.9K]

<h2> The given expression is equivalent to $x^{5}$ .</h2>

Step-by-step explanation:

The given expression is

$x^3.x^2$

To write the given expression is equivalent = ?

The given expression is

$x^3.x^2$

We know that,

The exponential identity,

$a^{m}.a^{n}=a^{m+n}$

= $x^{3+2}$

= $x^{5}$

∴ The given expression is equivalent = $x^{5}$

Thus, the given expression is equivalent to $x^{5}$ .

You can also see:

brainly.com/question/4456975

8 0

4 years ago

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Please help me solve this problem ASAP

DiKsa [7]

$\bold{\huge{\blue{\underline{ Solution }}}}$

<h3>Given :-</h3>

The right angled below is formed by 3 squares A, B and C
The area of square B has an area of 144 inches ²
The area of square C has an of 169 inches ²

We have to find the area of square A?

<h3>Let's Begin :- </h3>

The right angled triangle is formed by 3 squares

We have, 

Area of square B is 144 inches²
Area of square C is 169 inches²

We know that,

$\bold{ Area \: of \: square = Side × Side }$

Let the side of square B be x

Subsitute the required values,

$\sf{ 144 = x × x }$

$\sf{ 144 = x² }$

$\sf{ x = √144}$

$\bold{\red{ x = 12\: inches }}$

Thus, The dimension of square B is 12 inches

Area of square C = 169 inches

Let the side of square C be y

Subsitute the required values,

$\sf{ 169 = y × y }$

$\sf{ 169 = y² }$

$\sf{ y = √169}$

$\bold{\green{ y = 13\: inches }}$

Thus, The dimension of square C is 13 inches.

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3>Therefore, By using Pythagoras theorem, </h3>

The sum of squares of base and perpendicular height equal to the square of hypotenuse

That is,

$\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}$

Here, 

Base = x = 12 inches
Perpendicular = z
Hypotenuse = y = 13 inches

Subsitute the required values,

$\sf{ (z)² + (x)² = (y)² }$

$\sf{ (z)² + (12)² = (169)² }$

$\sf{ (z)² + 144 = 169}$

$\sf{ (z)² = 169 - 144 }$

$\sf{ (z)² = 25}$

$\bold{\blue{ z = 5 }}$

Thus, The dimensions of square A is 5 inches

<h3>Therefore,</h3>

Area of square

$\sf{ = Side × Side }$

$\sf{ = 5 × 5 }$

$\bold{\orange{ = 25\: inches }}$

Hence, The area of square A is 25 inches.

6 0

3 years ago

-3+4p=-31 idk what it is

OLga [1]

4p = -28
divide each side by 4
p = -7

4 0

3 years ago

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Consider parallelogram VWXY below.

olchik [2.2K]

note:Parallelogram WXYZ not VWXY & I will answer the questions in the image b'cos I don't get your question.

Answers:

a.(i.)Slope of line YZ = 4/5

(ii.)Line adjacent line YZ is line YX,slope of YX =5/4

b.(i.)Length of line YZ =√41 units

(ii.)Length of line YX =√41 units

c.WXYZ is a rhombus.

Step-by-step explanation:

a.Slope=gradient(m)=(y₂-y₁)/(x₂-x₁)

(i.)m of line YZ=(y₂-y₁)/(x₂-x₁) where Y(-6,-1) & Z(-1,3)

(I believe you know what the y₂,y₁,x₂ & x₁ stand for.)

So m=(y₂-y₁)/(x₂-x₁),=(3-(-1))/(-1-(-6) =(4)/(5)=4/5

∴m of line YZ is 4/5

(ii.)m of line YX=(y₂-y₁)/(x₂-x₁) where Y(-6,-1) & X(-2,4)

So m=(y₂-y₁)/(x₂-x₁),=(4-(-1))/(-2-(-6) =(5)/(4)=5/4=1.25

∴m of line YX is 5/4

b.(i.)To find the length of line YZ,we have to express it as column vector YZ.

Vector YZ=OZ-OY,Z-Y=(-1,3)-(-6,-1)=(5,4)

Length=√x² plus y²=√5² plus 4²=√25 plus 16=√41 units

∴The length of line YZ is √41 units.

(ii.)To find the length of line YX,we have to express it as column vector YZ.

Vector YX=OX-OY,X-Y=(-2,4)-(-6,-1)=(4,5)

Length=√x² plus y²=√4² plus 5²=√16 plus 25=√41 units

∴The length of line YX is √41 units.

c.WXYZ is a rhombus.

5 0

2 years ago

Consider the original complex figure and the reduction.

agasfer [191]

Answer: 1/8

Step-by-step explanation:

The reason why its 1/8 is because 32 times 1/8= 4

8 0

3 years ago

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