To solve for the time an object takes to hit the ground, the equation
<em>y</em> <em>= y₀ + v₀t + ½gt²</em>, or just <em>0 = y₀ +½gt²</em> since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, <em>t = (−2y₀/g)^½.</em>
(-2*60/-9.8)^½ = 3.50 seconds.
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Answer:
G. 7
Explanation:
The longest side must be less than the sum of the two shorter sides.
The difference between the longest and shortest sides must be less than the middle side.
l+a = 11
l < (a + 4) ... l < (11 - l + 4)
... 2 l < 15 ... l < 7.5
--Variables
l = 7 (Longest Side/Answer)
a = 4 (Other Missing Length)
m = 4 (Side Given)
Answer:
1:05 p.m
Step-by-step explanation:
they took 35 minutes...... and they arrived at 1:40 p.m so 40-35= 5 = 1:05 p.m :)
I assume the solid is a "regular hexagonal prism", by which it means that the cross section is a regular hexagon with all sides and angles equal.
Also, the exact apothem is 9.5262... but we will adopt the given value of 9.5.
First lateral surface area
A1=6*side length*height=6*11*20=1320 units
Then the end areas
A2=2 faces * 6 triangles/face * [base * height (apothem) /2]
=2*6*11*9.5/2
=627 units
Total area=1320+627=1947 units
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Yes, the 3 feet are important.
<span>You can consider the datum (y=0) at 3' from the ground, and the ground is therefore at -3 feet. </span>
<span>The vertical initial velocity, vy, is u*sin(θ), so it gives </span>
<span>vy=55sin(44°)=38.21 approx. </span>
<span>The (vertical) distance travelled is given by: </span>
<span>S=vy*t-(1/2)gt² </span>
<span>where </span>
<span>S=-3 (ground) </span>
<span>vy=55sin(44°), and </span>
<span>g=32.2 ft/s² </span>
<span>Solve for t. </span>
<span>I get -0.08 and 2.45 s.</span>
