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shutvik [7]
3 years ago
15

How do you solve quadratic equations?

Mathematics
1 answer:
masha68 [24]3 years ago
8 0
In any equation there is a variable (usually x). In a quadratic equation there is a lot involved.

-B (+or-) sqrt of b^2 - 4 x A x C
________________________  divide it by
               2 x A
                                                   There is usually an original equation that looks like:  Ax^2 + Bx + C = 0    Use the variables from the equation to the left to fill the upper equation.  (You can also look up a better formula if confused).

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C) Re-write the statement 19 + 7 = 2 x 6 + 1 by including two pairs of brackets
zaharov [31]

Answer:

1*(9+7):(2+6)*1=2    

Step-by-step explanation:

6 0
3 years ago
A combination lock requires three numbers from 1 to 25. how many combinations are possible? did you use the sum rule or the prod
maria [59]
Combinations possible = 25 * 25 * 25. Product rule

The point is that numbers can be reused. 1 5 1 is a valid combination as is   4 4 4 

20 * 5 * 1 is a valid combination as is 1 25 5

So the answer is 15625 "combinations" are possible <<<<< answer
7 0
3 years ago
Who’s can help me with this, it is to hard
vazorg [7]

Answer:

x = 10

MB = 16

CM = 16

CB = 32

Step-by-step explanation:

Since it's the mispoint

2x - 4 = x + 6

Subtract x from both sides

x - 4 = 6

Add 4 to both sides

x = 10

MB = 2x - 4

MB = 20 - 4

MB = 16

CM = x + 6

CM = 16

CB = 16 + 16

CB = 32

3 0
3 years ago
Which of the following represents a rational number?
Alexandra [31]

A.

Step-by-step explanation:

A is a rational number because it is a numerator p and a non-zero denominator w

8 0
3 years ago
PLEASE HELP AS SOON AS YOU CAN!!
Tasya [4]
The Answer would be -6(3x-5).
5 0
3 years ago
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