8x^3 -5x^2 + 8x + 9+5x^3 + 3x^2 - 5x + 4 =
8x^3+5x^3-5x^2 + 3x^2+ 8x - 5x+ 9<span>+ 4 = </span>
13x^3-2x^2+3x+13
Answer:
X = 11
X = 7
Step-by-step explanation:
Part 1:
The measure of an inscribed angle is half the measure of an intercepted arc. So 1/2 mCE = m∠CDE
158 ÷ 2 = 79
You need to find x so you're going to set your equation of (8x - 9) = 79
Then you're going to add 9 to both sides to get 8x = 88
Divide both sides by 8 to get x = 11
Part 2:
We know that WY is 180 because it's a semicircle. Using this and the knowledge that ∠WXY is half the measure of the intercepted arc (180), we know that our equation should be (13x - 1) = 90
add 1 to both sides and our equation is (13x = 91)
Divide both sides by 13 and...
x = 7
Answer:
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