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lara [203]
3 years ago
10

Solve 2x2 − 8x = −7.

Mathematics
2 answers:
maks197457 [2]3 years ago
8 0

Answer:

D.2 plus or minus the square root of 2 end root over 2

Step-by-step explanation:

leva [86]3 years ago
7 0
\sf 2x^2 - 8x = - 7  \\  \\ Subtract \ -7 \ from \ both \ sides \ of \ the \ equation. \\  \\ 2x^2 - 8x - (-7 ) = - 7 - (-7)  \\  \\ 2x^2 - 8x + 7 = 0  \\  \\ Use \ quadratic \ formula \ a = 2, b = -8, c = 7 \\  \\ x =  \dfrac{- b \pm \sqrt{b^2- 4ac} }{2a}  \\  \\  \\ x =  \dfrac{-(-8) \pm \sqrt{(-8)^2 - 4 (2) (7) } }{2(2)}  \\  \\ x =  \dfrac{8 \pm  \sqrt{8} }{4}  \\  \\ x = 2 +  \frac{1}{2}\sqrt{2} \ or \ x = 2 +  \frac{-1}{2}  \sqrt{2}

Ur answer is the fourth one 



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