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pickupchik [31]
3 years ago
13

What’s the least common denominator for 1/6 and 7/8?

Mathematics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

24

Step-by-step explanation:

Here's how we construct the LCD:

Factor the denominators 6 and 8:  6 = 2*3 and 8 = 2*2*2

The LCD involves 2*2*2 as well as 3:

LCD:  2*2*2*3 = 24.  Note that 24 is divisible by both 6 and 8.  There is no smaller LCD that is divisible by 6 and 8 both.

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Find a 2 × 2 matrix b ≠ o and b ≠ i2 such that ab = ba, where a = 1 7 0 1 . b =
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If \mathbf A is invertible, then we can simply choose \mathbf B=\mathbf A^{-1} because for any invertible matrix \mathbf X by definition we must have \mathbf{XX}^{-1}=\mathbf X^{-1}\mathbf X=\mathbf I.

We have \det\mathbf A\neq0, as

\det\mathbf A=\begin{vmatrix}1&7\\0&1\end{vmatrix}=1\times1-0\times7=1

which means \mathbf A is non-singular and has an inverse. The inverse itself would be

\mathbf A^{-1}=\dfrac1{\det\mathbf A}\begin{bmatrix}1&0\\-7&1\end{bmatrix}^\top=\begin{bmatrix}1&-7\\0&1\end{bmatrix}
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Answer:


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