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Reptile [31]
4 years ago
10

How many triangles can you construct with the angle measures of 50, 70, and 100?

Mathematics
1 answer:
lidiya [134]4 years ago
6 0

Answer:

0

Step-by-step explanation:

You can't construct any triangles with those angles. Because when you add all the angles of a triangle, it has to add up to 180. But when we add 50,70, and 100, it equals 220. So you can't construct any triangles.

Hope this helps.<em> (If it does, please mark me brainliest)</em>

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Verify sin^4x-sin^2x=cos^4x-cos^2x is an identity
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ANSWER

See below

EXPLANATION

We want to verify that,

{ \sin ^{4} x}  -  { \sin^{2} x} = { \cos ^{4} x}  -  {  \cos^{2} x}

To verify this identity, we can take the left hand side simplify it to get the right hand side or vice versa.

{ \sin ^{4} x}  -  { \sin^{2} x} =( { \sin ^{2} x} )^{2} -  { \sin^{2} x}

{ \sin ^{4} x}  -  { \sin^{2} x} ={ \sin ^{2} x}({ \sin ^{2} x}  - 1)

{ \sin ^{4} x}  -  { \sin^{2} x} ={ \sin ^{2} x} \times  - (1 - { \sin ^{2} x})

{ \sin ^{4} x}  -  { \sin^{2} x} =({1 -  \cos^{2} x} )\times  - ({ \cos^{2} x})

{ \sin ^{4} x}  -  { \sin^{2} x} =({ \cos^{2} x} - 1 )\times  ({ \cos^{2} x})

We now expand the right hand side to get:

{ \sin ^{4} x}  -  { \sin^{2} x} = { \cos ^{4} x}  -  {  \cos^{2} x}

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Step-by-step explanation:

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