1) Because 
is a central angle, 
.
Since and 
are supplementary, they form a linear pair, and thus 
5) Tangents drawn from an external common point are congruent, so CR=CP=8 and RB=BQ=4. This means that QA=11, and so PA=11 as well. Adding CP+PA, we get AC=19.
6) By the inscribed angle theorem, angle QPR measures 36 degrees.
I just plugged both equations into my calculator and found where they intersect. But you can do the same on paper by manually finding that intersection in the graph which should be (2,4)
Answer:
I think you mean ‘repetition’ of digits is not allowed when you say ‘terrain' of digits is not allowed. If it is so, I will proceed further.
Three digit numbers have Hundreds place, Tens place and Units place. There are six digits, 1,2,3,4,5 and 6 are available. The Hundreds place can be filled up by any one of these 6 digits and can therefore be filled up in 6 ways. Since repetition of digits is not allowed we are left with 5 digits to fill up the Tens place. So Tens place can be filled up in 5 ways. Using the same argument we can fill up the Units digit in 4 ways. Hence we can form (6)(5)(4) = 120 numbers of three digits using the digits 1,2,3,4,5,6 without repetition.
Step-by-step explanation:
1. y=4x+5
2. y=2+6x
3. y=8-x
Answer:
3n^2 -5n -6 = 9 This is a quadratic Equation.
3n^2 -5n -15 = 0
It is solved with the Quadratic Formula:
n = [-b +-sqr root (b^2 - 4ac)] / 2a
a = 3
b = -5
c= -15
n = [--5 +- sqr root(25 -4*3*-15)] / 6
n = [5 +- sqr root (25 + 180) / 6
n = [5 +-sqr root (205) ] / 6
n = 5 + 14.3178210633 / 6
n1 = 19.3178210633 / 6
n1= 3.2196368439
n2= 5 - 14.3178210633 / 6
n2 = -9.3178210633 / 6
n2 = -1.5529701772
Step-by-step explanation:
