This system of equations has no solution.
Answer:
60cm^2
Step-by-step explanation:
We assume that is a circumscribing quadrilateral, rather than one that is circumscribed. It is also called a "tangential quadrilateral" and its area is ...
K = sr
where s is the semi-perimeter, the sum of opposite sides, and r is the radius of the incircle.
K = (12 cm) (5cm) = 60 cm²
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A quadrilateral can only be tangential if pairs of opposite sides add to the same length. Hence the given sum is the semiperimeter.
Using the mean concept, it is found that:
Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.
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The mean of a data-set is given by the <u>sum of all observations divided by the number of observations</u>.
In this problem:
- The data-set is her swim time relative to her goal, which is: {1.25, -1, 2.25, 0, -2.}
Thus, the mean is:

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.
A similar problem is given at brainly.com/question/24787716
Answer:
The figure is attached and the total distance is 1031 feet.
Step-by-step explanation:
The graph is indicated in the attached figure.
For calculation of distance consider following
Point Flagpole is (0,0)
Point Clue1 is (0,5)
Point Clue2 is (6,0)
Point Clue3 is (0,-5)
So the distance is calculated as follows
Substituting the values
![d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5B%5Csqrt%7B%280-0%29%5E2%2B%285-0%29%5E2%7D%2B%5Csqrt%7B%286-0%29%5E2%2B%280-5%29%5E2%7D%2B%5Csqrt%7B%280-6%29%5E2%2B%28-5-0%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%280%29%5E2%2B%285%29%5E2%7D%2B%5Csqrt%7B%286%29%5E2%2B%28-5%29%5E2%7D%2B%5Csqrt%7B%28-6%29%5E2%2B%28-5%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B0%2B25%7D%2B%5Csqrt%7B36%2B25%7D%2B%5Csqrt%7B36%2B25%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B25%7D%2B%5Csqrt%7B61%7D%2B%5Csqrt%7B61%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B5%2B7.81%2B7.81%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B20.62%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D1031%20%5Ctext%7B%20feet%7D%5C%5C)
So the total distance travelled is 1031 feet.