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4 years ago

3y+3 (1-y)-y=-6PLEASE help

Mathematics

1 answer:

Murrr4er [49]4 years ago

7 0

3y+4+3y-y=-6
6y-y+4=-6
5y+4=-6
5y=-10
y=-2
If you have any questions let me know

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Solve each given equation and show your work the whether each equation has one solution, an infinite number of solutions, or no

Triss [41]

2x+4x-4=2+4x
2x+4x-4x=2+4
2x=6
x=3

25-x=15-3x-10
3x-x= 15-10-25
2x= -20
x= -10

4x=2x+2x+5x-5x
2x+2x+5x-5x-4x
0 . no solution

8 0

3 years ago

Round 3,942,588 to the nearest thousand.

olchik [2.2K]

Hey there! :D

3,942,588

The thousandths is where the 2 is.

If the number behind the 2 is 5 or greater, we round up to 3.

It is, so round up:

3,943,000 <== rounded number

I hope this helps!
~kaikers

5 0

3 years ago

Read 2 more answers

Geometry. Please help ASAP.

neonofarm [45]

Please see the pic, I'd solved your question in it.

6 0

3 years ago

The length of a rectangular garden is 17 feet longer than its width. If the area of the garden is 234 square feet, what are the

kifflom [539]

Answer:

The garden is 9 feet wide and 26 feet long.

Step-by-step explanation:

L = W+17

area = LW = 234

(W+17)W = 234

W²+17W-234 = 0

Quadratic formula

W = [-17 ± √(17² – 4·1(-234))] / [2·1]

= [-17 ± √1225] / 2

= [-17 ± 35] /2

= -26, 9

-26 is an extraneous solution

W = 9

L = W+17 = 26

The garden is 9 feet wide and 26 feet long.

3 0

3 years ago

When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p w

deff fn [24]

Answer:

A 90% confidence interval for p will be narrower than the 99% confidence interval.

Step-by-step explanation:

The formula to compute the (1 - α) % confidence interval for a population proportion is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Here $\hat p$ is the sample proportion.

The margin of error of the confidence interval is:

$MOE= z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The MOE is dependent on:

Confidence level
Standard deviation
Sample size

The MOE is directly related to the confidence level and standard deviation.

So if any of the two increases then the MOE also increases, thus widening the confidence interval.

And the MOE is inversely related to the sample size.

So if the sample increases the MOE decreases and vice versa.

It is provided that the sample size and the sample proportion are not altered.

The critical value of z for 90% confidence level is:

$z_{\alpha/2}= z_{0.10/2}=z_{0.05}=1.645$

And the critical value of z for 99% confidence level is:

$z_{\alpha/2}= z_{0.05/2}=z_{0.05}=1.96$

So as the confidence level increases the critical value increases.

Thus, a 90% confidence interval for p will be narrower than the 99% confidence interval.

6 0

3 years ago