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muminat
3 years ago
11

A dependent system of equations is a system with __________.. . the same line. . parallel lines. . intersecting lines and lines

that have the same equation. . intersecting lines and lines that have the same slope
Mathematics
2 answers:
Mazyrski [523]3 years ago
5 0
A dependent system of equations is a system with the same line. The correct option among all the options that are given in the question is the first option. It will become clear to you, once you draw this yourself. I hope the answer has come to your help.
erica [24]3 years ago
4 0

Answer:

The same lines

Step-by-step explanation:

The same lines will form a dependent system of equations.

This is because when two lines are coincident we have say lines as the same.

If the same line is of the form say

ax+by=c

THis time we can write (x,y) as y = (c-ax)/b

Thus solution would be

ordered pair

(x,\frac{c-by}{a}

Thus dependent solution

But parallel lines do not have solution at all, while intersecting lines have unique solution.

So answer is same lines

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A rectangular prism has a length of 1 1/2 meters, a width of 3 meters, and a height of 5 1/2 meters.
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Answer:

13m

Step-by-step explanation:

because i use calculator soup

4 0
2 years ago
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Which equation is equivalent to 3/4=2x-1/2y+4
lyudmila [28]

Answer:

option a and d

Step-by-step explanation:

\frac{3}{4}  =  \frac{2x - 1}{2y + 4} \\ 3(2y + 4) = 4(2x - 1) \\ 6y + 12 = 8x - 4 \\ now \\ 6y = 8x - 4 - 12 \\ 6y = 8x - 16 \\ y =  \frac{8x - 16}{6} \\   y =  \frac{8x}{6}  -  \frac{16}{6}  \\ y =  \frac{4x}{3}  -  \frac{8}{3}  \\ y =  \frac{4}{3} x -  \frac{8}{3}  \\a nd \\  \\ 6y + 12 = 8x - 4 \\  6y + 12 + 4 = 8x \\ 6y + 16 = 8x \\  \frac{6y + 16}{8}  = x \\  \frac{6y}{8}   +  \frac{16}{8}  = x \\  \frac{3y}{4}  + 2 = x \\  x = \frac{3}{4} y + 2

6 0
3 years ago
What is the approximate length of RP? Round to the nearest tenth.
sergiy2304 [10]
Use Pythagorean Theorem:
c = sr (a^2 + b^2) = sr (3^2 + 5.3^2)
= sr (9 + 28.09) = sr (37.09)
= 6.09 = 6.1
7 0
4 years ago
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Help!!!!!!!!!!!!!!!!
Andru [333]

Step-by-step explanation:

The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:

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let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9

let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9

let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9

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You can continue to increase the length of the square and follow this pattern and it will be consistent.

7 0
3 years ago
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If you're seeing these problems as part of your study of statistics, you should know that
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Then C(7, 7) = 7!/(7!×0!) = 1/0!
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This is the number of ways you can choose 7 objects from a pool of 7 objects without regard to order. (You can do it one (1) way: choose all of them.)

The appropriate choice is ...
  B: 1
7 0
3 years ago
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