Answer:
13m
Step-by-step explanation:
because i use calculator soup
Answer:
option a and d
Step-by-step explanation:

Use Pythagorean Theorem:
c = sr (a^2 + b^2) = sr (3^2 + 5.3^2)
= sr (9 + 28.09) = sr (37.09)
= 6.09 = 6.1
Step-by-step explanation:
The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:
let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9
let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9
let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9
let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9
let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9
let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9
You can continue to increase the length of the square and follow this pattern and it will be consistent.
If you're seeing these problems as part of your study of statistics, you should know that
C(n, k) = n!/(k!×(n-k)!)
where the "!" indicates the factorial, the product of all positive integers less than or equal to the given one.
Then C(7, 7) = 7!/(7!×0!) = 1/0!
You are supposed to know also that 0! ≡ 1, so C(7, 7) = 1.
This is the number of ways you can choose 7 objects from a pool of 7 objects without regard to order. (You can do it one (1) way: choose all of them.)
The appropriate choice is ...
B: 1