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muminat
3 years ago
11

A dependent system of equations is a system with __________.. . the same line. . parallel lines. . intersecting lines and lines

that have the same equation. . intersecting lines and lines that have the same slope
Mathematics
2 answers:
Mazyrski [523]3 years ago
5 0
A dependent system of equations is a system with the same line. The correct option among all the options that are given in the question is the first option. It will become clear to you, once you draw this yourself. I hope the answer has come to your help.
erica [24]3 years ago
4 0

Answer:

The same lines

Step-by-step explanation:

The same lines will form a dependent system of equations.

This is because when two lines are coincident we have say lines as the same.

If the same line is of the form say

ax+by=c

THis time we can write (x,y) as y = (c-ax)/b

Thus solution would be

ordered pair

(x,\frac{c-by}{a}

Thus dependent solution

But parallel lines do not have solution at all, while intersecting lines have unique solution.

So answer is same lines

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ivanzaharov [21]

Answer:

Z=BY+R

Step-by-step explanation:

B=z-r/y

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Simple easy stuff should have no problems. I would love some more math like this bring it. C:

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3 years ago
Please help me answer this for a test im having trouble
Dimas [21]

Answer:

x + 1

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Step-by-step explanation:

In order to solve this question we need to represent "y "in terms of "x" in the first equation, and the plug in the "y" value in the first equation into the second one. Luckily for us in the first equation it already shows what "y" is equal to in terms of "x" (based on the first equation y = -x + 10). Now we just need to plug in the value that we got instead of "y" in the second equation, and so we get....

y = 7x + 2

(plug in the y value and get the following ….)

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(now just solve the following equation)

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Now that we know the value of "x", all we need to do now is substitute the value of "x" into any of the equations and we will get the value of "y". So we do the following.....

y =  7x + 2

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prisoha [69]

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