The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
Slope intercept form looks like:
y = mx + b
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Choose the one that follows the formula
B) y=-2x+15 is your answer.
-2 = m
15 = b
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hope this helps
sorry but i don't know english friend if i knew i would tell you this time i failed
This looks like a second half of a question. are you sure this is the full question?
Answer:
B
Step-by-step explanation:
Our system of equations is:
3x + y = 23
8x + 2y = 23
If we want to use substitution, that means that we essentially want to manipulate one of the two equations so that one variable (like y) is written in terms of the other (like x), and then substitute that expression into the second equation so that we have one variable and one equation and we can easily solve from there.
So the first thing to be done is to write one of the variables in terms of the other. It would be easiest to do it with the first equation and write y in terms of x - in other words, "solve the first equation for y".
The answer is B.
