1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksandr82 [10.1K]
3 years ago
11

During a bite challenge rattlers how to collect various colored ribbons each 1/2 mile they collect a red ribbon each 1/8 mile th

ey collect a green ribbon and each 1/4 mile they collect a blue ribbon which colors or ribbons will be collected
Mathematics
2 answers:
tino4ka555 [31]3 years ago
7 0
1/2×4=4/8
1/8=1/8
1/4×2=2/8
so 4/8+2/8=6/8
and 6/8+1/8=7/8

so 7/8 ribbons will be collected
AleksAgata [21]3 years ago
4 0

Question

During a bike challenge, riders have to collect various colored ribbons. Each 1/2 mile they collect a red ribbon, each 1/8 mile they collect a green ribbon, and each 1/4 mile they collect a blue ribbon. Which colors of ribbons will be collected at the 3/4 mile marker?

Answer:

A green and a blue ribbon will be collected at the  \frac{3}{4} mile marker.

Step-by-step explanation:

<em>Topic: Factors and Multiples</em>

<em></em>

To solve this, we'll write out the first few multiples of the distances where the collection of ribbons occurs:

Given that each \frac{1}{2} mile they collect a red ribbon; The multiples for the Red Ribbon are as follows (by adding \frac{1}{2} at each progression):

Red: \frac{1}{2}  -> {1}{}  -> \frac{3}{2}  -> {2}{}  -> \frac{5}{2}

Given that each \frac{1}{8} mile they collect a green ribbon; The multiples for the Green Ribbon are as follows (by adding \frac{1}{8} at each progression):

Green: \frac{1}{8}  -> \frac{1}{4}  -> \frac{3}{8}  -> \frac{1}{2}  -> \frac{5}{8} -> \frac{3}{4}  -> \frac{7}{8}  -> {1}

Given that each \frac{1}{4} mile they collect a blue ribbon; The multiples for the Blue Ribbon are as follows (by adding \frac{1}{4} at each progression):

Blue: \frac{1}{4} -> \frac{1}{2}  -> \frac{3}{4}  -> {1}

Since , \frac{3}{4} is a multiple of both  \frac{1}{8} and \frac{1}{4} , then a green and a blue ribbon will be collected at the  \frac{3}{4} mile marker.

You might be interested in
Help me out with these please!<br><br> No links to suspicious sites!
weeeeeb [17]

Answer:

1) N = 2. 2) -7/3

Step-by-step explanation:

1)

6 = 3n

6/3 = n

2 = n

n = 2

2)

-3 = 3t + 4

3t + 4 = -3

3t = -3 - 4

3t = -7

T = -7/3

5 0
3 years ago
Read 2 more answers
5 - x - x = -1 PLEASE SOLVE AND SHOW WORK!
siniylev [52]
5 - X - X = -1
5 - 2x = -1
-2x = -1 - 5
-2x = -6
X = 3.
6 0
4 years ago
PLS HELP ASAP! GIVING BRAINLIST
garri49 [273]

Answer:

8.48528137424

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Four times a number subtracted from ten is twice the number
sertanlavr [38]

Answer:

4 times x -10 times 2

i think

Step-by-step explanation:

7 0
3 years ago
The ages (in years) and weights (in pounds) of all wide receivers for a football team are listed. Find the coefficient of variat
IceJOKER [234]

Answer:

The coefficient of variation for the weight and age are 5.9% and 10.6%.

Step-by-step explanation:

The coefficient of variation (CV) is well defined as the ratio of the standard deviation to the mean. It exhibits the degree of variation in association to the mean of the population.

The formula to compute the coefficient of variation is:

CV=\frac{\sigma}{\mu}\times 100\%

Here σ = standard deviation and µ = mean.

Compute the mean and standard deviations of the two data set in Excel using the following functions.

Mean=AVERAGE()

Standard deviation=STDEV.S()

Consider the Excel sheet attached.

The mean and standard deviation of weight are:

Mean = 202, Standard deviation = 11.87

And the mean and standard deviation of weight are:

Mean = 25.88, Standard deviation = 2.75

Compute the coefficient of variation for the weight as follows:

CV_{weight}=\frac{\sigma}{\mu}\times 100\%

              =\frac{11.87}{202}\times 100\%\\\\=5.87624\\\\=5.9\%

Compute the coefficient of variation for the age as follows:

CV_{age}=\frac{\sigma}{\mu}\times 100\%

              =\frac{2.75}{25.88}\times 100\%\\\\=10.62597\\\\=10.6\%

Thus, the coefficient of variation for the weight and age are 5.9% and 10.6%.

8 0
3 years ago
Other questions:
  • I don't understand this kind of math and need help
    14·1 answer
  • a random number generator is used to select an integer from 1 to 200 inclusively what is the probability of selecting the intege
    6·1 answer
  • First one right gets BRAINLIEST!!<br><br> If f(x)=x²+2x-3 and g(x)=x²-9, find (f/g) 4 and (f+g)(4)
    9·1 answer
  • Plz help <br> z + 8+2 over 3 £-4
    5·1 answer
  • Find the perimeter ​
    6·2 answers
  • Suppose the distributor charges the artist a $40.00 cost for distribution, and the streaming services pays $4.00 per unit. (Note
    13·1 answer
  • Pleaseee help me which one is it????
    13·1 answer
  • Does anyone know what is a passing grade in high school?
    15·1 answer
  • Which ratio is equivalent to 3:18
    15·2 answers
  • Can you show me how to solve this?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!