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Mnenie [13.5K]
3 years ago
11

Rectangle A and B have the same Area. Rectangle A has a length of 7m and a width of 4m. Rectangle B has a width of 10m. What is

the perimeter of Rectangle B? *
Mathematics
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

P = 25.6 feet

Step-by-step explanation:

Given that,

Rectangle A and B have the same Area.

The area of a rectangle is given by :

A = lb

l_Ab_A=l_Bb_B

We have,

l_A=7\ m, b_A=4\ m, b_B=10\ m

So,

l_B=\dfrac{l_Ab_A}{l_B}\\\\l_B=\dfrac{7\times 4}{10}\\\\l_B=2.8\ m

The perimeter of rectangle B,

P=2(l_B+b_B)\\\\=2(2.8+10)\\\\=25.6\ ft

So, the perimeter of rectangle B is equal to 25.6 feet.

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(3.8 x 10 ^ -6) x (2.37 x 10 ^ -3)<br><br> Enter the answer in science notification
Black_prince [1.1K]

Multiply the coefficients and the powers of 10 with each other:

(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})

The numeric part simply yields

3.8\times2.37 = 9.006

As for the powers of 10, you have to add the exponents, using the rule

a^b \times a^c = a^{b+c}

So, we have

10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}

So, the final answer is

9.006\times 10^{-9}

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3 years ago
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3 years ago
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Answer:

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