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3 years ago

6

While waiting for a video game to download, you notice that 30% percent of 32,000 kilobytes have been downloaded so far. How man

y kilobytes have been downloaded so far?

1 answer:

DiKsa [7]3 years ago

4 0

32000(0.3)=9,600

9,600 kilobytes have been downloaded so far.

Hope this help!

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Please help Use the expression 8a + 16c.

alexdok [17]

Answer:

C 89a + 2c)

Step-by-step explanation:

The largest factor of both 8 and 16 is 8. So, 8 = GCF

factor out an 8 and you get 8(a + 2c)

To check if you are correct, multiply and see if you get what you started with.

3 0

3 years ago

Read 2 more answers

What digits makes 3,71? Divisible by 3 (connections academy unit test)

wlad13 [49]

Since we know that a number is divisible by 3 if the sum of all digits is divisible by 3.

Let us check which digits will make 371? divisible by 3.

$3+7+1+0=11$

11 is not divisible by 3.

Now let us check other digits as well.

$3+7+1+1=12$

12 is divisible by 3.

$3+7+1+4=15$

15 is also divisible by 3.

$3+7+1+7=18$

18 is divisible by 3 as well.

Therefore, 1, 4 and 7 in tenth place will make our number divisible by 3 and our numbers will be 3711, 3714 and 3717.

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3 years ago

PLS ANSWER FAST 15POINTS ❗️❗️❗️❗️❗️❗️

o-na [289]

Answer:

300 cubic meters

Step-by-step explanation:

Volume of a Rectangular pyramid:

V = (lwh)/3

Given:

l = 10

w = 10

h = 9

Work:

V = (lwh)/3

V = (10 * 10 * 9)/3

V = 900/3

V = 300

4 0

3 years ago

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Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

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3 years ago

8.25 × 10–4 in standard form.

Elanso [62]

The 10^-4 means that the decimal point is 4 places to the left of where it is in 8.25 (if the exponent was positive the decimal point would be to the right). If you move the decimal point 4 places to the left you get an answer of 0.000825 which is 8.25 * 10^-4 in standard form.

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3 years ago