B is the answer i'm positive
Answer:
1) Categorical
2) Norminal
Step-by-step explanation:
1)
The data collected by Kroger in this example categorical or quantitative identified below:
From the given information, Kroger uses an online customer opinion to obtain the data about its products and services. All the questions based on yes or no type questions. Here the questions are ‘products that have a brand name, products that are environmentally friendly, products that are organic’ these type of questions cannot be expressed numerically so the data collected by Kroger Company is categorical variable because these answers of the questions cannot be counted.
Any variable which is grouped into two or more attributes then it is a categorical variable. The data collected by Kroger Company is categorical variable and any variable which can be counted or measured in numerical then it is quantitative variable.
2)
The measurement scale is identified below:
Here the variable cannot be counted in numerical sale so the level of measurement cannot be ratio, interval because ratio and interval scale can be used for numerical data. The nominal scale can be used to identify the ‘products that have a brand name, products that are environmentally friendly, products that are organic, products that have been recommended by others’ because natural order need not be used.
The ratio and interval scale can be used for Quantitative data and nominal and ordinal scale can be used for Qualitative data. When the order is needed to categorize the objects Ordinal scale is used, when the order is not needed to categorize the objects Nominal scale is used.
Answer:
45
Step-by-step explanation:
If "a" and "b" are two values of x-coordinate, and "m" is the midpoint between them, it means the distance from one end to the midpoint is the same as the distance from the midpoint to the other end
... a-m = m-b
When we add m+b to this equation, we get
... a+b = 2m
Solving for m gives
... m = (a+b)/2
This applies to y-coordinates as well. So ...
... The midpoint between (x1, y1) and (x2, y2) is ((x1+x2)/2, (y1+y2)/2)
_____
Jennifer had (x1, y1) = (-4, 10) and (x2, y2) = (-2, 6). So her calculation would be
... midpoint = ((-4-2)/2, (10+6)/2) = (-6/2, 16/2) = (-3, 8)
Brandon had (x1, y1) = (9, -4) and (x2, y2) = (-12, 8). So his calculation would be
... midpoint = ((9-12)/2, (-4+8)/2) = (-3/2, 4/2) = (-1.5, 2)
