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tensa zangetsu [6.8K]
3 years ago
10

What is the solution to the equation below?3log_4x=log_43 2+log_4 2

Mathematics
1 answer:
cupoosta [38]3 years ago
6 0
\frac{3\log _4\left(x\right)}{3}=\frac{\log _4\left(32\right)}{3}+\frac{\log _4\left(2\right)}{3}
Simplify
\log _4\left(x\right)=\frac{\log _4\left(32\right)+\log _4\left(2\right)}{3}
\log _4\left(x\right)=1
Apply log rule
\log _4\left(x\right)=\log _4\left(4\right)
Answer:
x=4
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