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Rudik [331]
3 years ago
6

What classes do you take in the 11th grade year ?

Mathematics
1 answer:
anygoal [31]3 years ago
3 0
When u are going to 11 grade u have to at least take AP calculus or calculus
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Data from the Centers for Disease Control and Prevention indicate that weights of American adults in 2005 had a mean of 167 poun
sesenic [268]

Answer:

92.65% probability that the total weight in a random sample of 47 American adults exceeds 7500 pounds in 2005.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums the theorem can also be used, with mean n*\mu and standard deviation s = \sqrt{n}*\sigma

In this problem, we have that:

n = 47, \mu = 47*167 = 7849, s = \sqrt{47}*35 = 240

Use this information to estimate the probability that the total weight in a random sample of 47 American adults exceeds 7500 pounds in 2005.

This is 1 subtracted by the pvalue of Z when X = 7500. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{7500 - 7849}{240}

Z = -1.45

Z = -1.45 has a pvalue of 0.0735

1 - 0.0735 = 0.9265

92.65% probability that the total weight in a random sample of 47 American adults exceeds 7500 pounds in 2005.

5 0
3 years ago
Classify the number (choose all that apply): 3/4
Igoryamba

Answer:

What are the answer choices? I would help but you didn't attach or write them.

Step-by-step explanation:

5 0
4 years ago
Find x3 - 2y2 - 3x3 + z4 if x = 3, y = 5, and z = -3.
zloy xaker [14]
So will be 27 -50 - 81 +81 = - 23

hope this will help you 
6 0
3 years ago
Read 2 more answers
Find the value of Y
Nadya [2.5K]
The answer is D.

this is unnecessary because i have to have twenty characters<span />
6 0
3 years ago
Read 2 more answers
For the two numbers listed find two factors of the first number such that their product is the first number and there sum is the
Ivanshal [37]

Given:

Product of two numbers is 24

Sum of two numbers is -11

-8 and -3 are the two numbers.

7 0
1 year ago
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