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Stolb23 [73]
3 years ago
9

Can a line plot be used to display data from a histogram

Mathematics
1 answer:
Anettt [7]3 years ago
6 0
Yes absolutely it totally can be used both ways  
You might be interested in
The center of a circle bs located at 3,9), and the evde hesa vedles that to sustain What the parengtame een hee)
tigry1 [53]

Answer:

The general equation of a circle is x2 + y2 - 6x - 16y + 48 = 0

Step-by-step explanation:

7 0
3 years ago
4,400 X 400 = ( blank hundreds) X ( blank hundreds) = 176 hundreds, thousands, hundrenths, tenths, tens, ones, thousands, or tho
kiruha [24]
Hello There!

(44 hundreds) x (4 hundreds) = 176 tens thousands.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
5 0
3 years ago
How many different ways can you write a fraction that has a numerator of 2 as a sum of fractions
Rzqust [24]
At least you can write it as the sum of half of it twice, that is:
2/x = 1/x + 1/x
whatever x number you have, for example:
2/5 = 1/5 + 1/5

But then, you can express a fraction in many different ways, for example again:
2/5 = <span>1/5 + 1/5 = 2/10 + 2/10
</span>= 1/10 + 1/10 + 1/10 + 1/10
so there are an infinite ways of expressing such a fraction.
7 0
3 years ago
Y=6x-1, y=3x-4 the solution is_____
TEA [102]

Answer:

y= -7 and x= -1

Step-by-step explanation:

To do this, line up the variables so it looks like this...

y-6x=-1

y-3x=-4

The reason why -6x and -3y changes to negative is because that it moved to the other side of the equation.

distribute negative to the bottom equation because the two equations have the same number variable which is y...

y-6x=-1

-y+3x=4

Y cancels out and it will be left with -3x = 3.

X = -1.... plug that in to any of the two equation and you get y = -7.

Hope I helped and have a nice day!!

5 0
2 years ago
a geometric series where the first term is -12, the last term is -972, and each term after the first is triple the previous term
Luba_88 [7]

Answer:

the geometric series is a(n) = -12(3)^(n-1)

Step-by-step explanation:

"Triple" denotes multiplication by 3.  Thus, the common factor here is 3.

The general formula for a geometric series is a(n) = a(1)(r)^(n-1), where a(1) is the first term, r is the common ratio.

Here, we have a(n)= (-12)(3)^(n-1) = -972.

We need to solve this for n, which represents the last term.

The first step towards solving for n is to divide both sides by -12:

3^(n-1) = 81

To solve for n-1, rewrite 81 as 3^4.  Then we have:

3^(n-1) = 3^4, implying that (n-1) = 4 and that n = 5.

Then we know that it is the 5th term that equals -972.

In summary, the geometric series is a(n) = -12(3)^(n-1).

8 0
3 years ago
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