Answer:
You are given:
4Fe+3O_2 -> 2Fe_2O_3
4:Fe:4
6:O_2:6
You actually have the same number of Fe on both sides, The same is true for O_2 so yes this equation is properly balanced.
For added benefit consider the following equation:
CH_4+O_2-> CO_2+2H_2O
ASK: Is this equation balanced? Quick answer: No
ASK: So how do we know and how do we then balance it?
DO: Count the number of each atom type you have on each side of the equation:
1:C:1
4:H:4
2:O:4
As you can see everything is balanced except for O To balance O we can simply add a coefficient of 2 in front of O_2 on the left side which would result in 4 O atoms:
CH_4+color(red)(2)O_2-> CO_2+2H_2O
1:C:1
4:H:4
4:O:4
Everything is now balanced.
Step-by-step explanation:
2(x+2) = 60
x+2 = 30
x = 28
The correct answer is C
It’s 2.26 (now I am going to write random stuff bc it says I need to have 20 characters ggvjffdffvhkjhv)
Answer:
(-6,-1)
Step-by-step explanation:
Answer:
x = 4
Step-by-step explanation:
<C = <A
25° = 8x - 7
32 = 8x
x = 4
