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Goryan [66]
3 years ago
12

Find the least number with factors 11, 23, and 37.

Mathematics
1 answer:
stich3 [128]3 years ago
6 0

23,11,37

least numbers


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Sophia has $6,000 to invest. She is considering two investment options.
dlinn [17]
Your answers are: Option A, because the investment will have a greater value.

And..... Option B, The investment will have a greater value.
8 0
3 years ago
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I. In a shipment of 300 connecting rods, the mean tensile strength is found to be 45 kpsi and has a standard deviation of 5 kpsi
CaHeK987 [17]

Answer:

a) Between 39 and 40 rods can be expected to have a strength less than 39.4 kpsi.

b) 260 rods are expected to have a strength between 39.4 and 60 kpsi

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 45, \sigma = 5

(a) Assuming a normal distribution, how many rods can be expected to have a strength less than 39.4 kpsi?

The percentage of rods with a stength less than 39.4 is the pvalue of Z when X = 39.4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.4 - 45}{5}

Z = -1.12

Z = -1.12 has a pvalue of 0.1314

13.14% of rods have a strength less than 39.4 kpsi.

Out of 300

0.1314*300 = 39.42

Between 39 and 40 rods can be expected to have a strength less than 39.4 kpsi.

(b) How many are expected to have a strength between 39.4 and 60 kpsi?

The percentage of rods with a stength in this interval is the pvalue of Z when X = 60 subtracted by the pvalue of Z when X = 39.4. So

X = 60

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 45}{5}

Z = 3

Z = 3 has a pvalue of 0.9987

X = 39.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.4 - 45}{5}

Z = -1.12

Z = -1.12 has a pvalue of 0.1314

0.9987 - 0.1314 = 0.8673

86.73% of the rods are expected to have a strength between 39.4 and 60 kpsi

Out of 300

0.8673*300 = 260

260 rods are expected to have a strength between 39.4 and 60 kpsi

4 0
4 years ago
We have 25% off coupon for a Christmas tree already marked down to 10% if the original price of the tree is 189 how much will sh
Vladimir [108]

Answer:

She will pay $122.85

Step-by-step explanation:

First, find the amount of the percents.

To do that, turn the percents into decimals.

25% --> 0.25

10% --> 0.10

Then, multiply each decimal with the original price.

189×0.25= 47.25

189×0.10= 18.90

Now that you have the amount of the percents, subtract both from the original price.

189- (47.25+18.90)

189-66.15= 122.85

5 0
3 years ago
Find the common factor of all the terms of the polynomial below<br><br> 49y^3-7y^2+14y
Alecsey [184]
<span>49y^3-7y^2+14y

= 7y(7y^2 - y + 2)</span>
5 0
3 years ago
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The picture is the question​
allsm [11]

Answer:

-4 points

Step-by-step explanation:

Since each incorrect answer is worth the same amount of negative points, use the equation below.

3x = -12      DIvide both sides by 3

x = -4 points  

8 0
3 years ago
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