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Semmy [17]
4 years ago
11

Help plz!!!!!!!!!!!!!!!

Mathematics
1 answer:
Alex777 [14]4 years ago
6 0
12n + 8 respectively
You might be interested in
How is 35 to 10 proportional to 7 to 5
KiRa [710]
If you simplify 35/10 both side divide by 7 is equal to 7/5

6 0
3 years ago
the sum of two numbers is 70. the larger number is five less than twice the smaller number . what are the two numbers
earnstyle [38]
X+y=70
x=2y-5
x=larger number
y=smaller number
now plug in the value of x to only have one variable in the equation...
Way to solve for y:
(2y-5)+y=70
3y-5=70
add 5 on both sides...
3y=75
divide by 3 on both sides
y=25
1st way to solve for x:
now plug in y in the original equation...
x+25=70
subtract 25 on both sides...
x=45
2nd way to solve for x:
plug in y for the second equation...
x=25(2)-5
x=50-5
x=45
answer: the two numbers are 45 and 25.

3 0
3 years ago
Compare (-18) + (-15) -23 ____15-18+23
lesya [120]

Alright here we go...

<u>(-18) + (-15) - 23</u>

-33 - 23

= -56

<u>15-18+23</u>

-3 + 23

= 20

so I don't know how you want me to compare it but,

(-18) + (-15) - 23 < 15-18+23

6 0
3 years ago
You rent an apartment that costs $1700 per month during the first year, but the rent
ozzi

so the first year is $1700

in that case: a(1)=1700

each year it goes up by $70

then in nth year it's: a(n)=a(n-1)+70

6 0
2 years ago
A snowstorm dropped three and two-fifths inches of snow. The next day one and four-fifths inches melted, how much snow was left?
boyakko [2]

Answer:

After the melting there were one and three fifths of snow left.

Step-by-step explanation:

Given that a snowstorm dropped three and two-fifths inches of snow, and the next day one and four-fifths inches melted, the following calculation must be performed to determine how much snow was left:

2/5 = 0.40

4/5 = 0.80

3.40 - 1.80 = X

1.60 = X

0.60 = 3/5

Thus, after the melting there were one and three fifths of snow left.

4 0
3 years ago
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