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2 years ago

15

This is a tricky onen ÷ 9 = 14

1 answer:

PSYCHO15rus [73]2 years ago

3 0

Answer:

n=126

Step-by-step explanation:

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True or false: Two lines with undefined slopes are parallel to each other and parallel to the y axis

BlackZzzverrR [31]

Correct! lines that have undefined slopes are always parallel to the y-axis as the change in x is 0. A gradient is calculated by the change in y divided by the change in x and anything divided by 0 is referred to as undefined.

$\frac{y_{1}- y_{2} }{x_{1}- x_{2} }$

(calculation for a gradient)

Hope that helps sorry if its a bit confusing :)

5 0

2 years ago

2. R = PN + C<br> Solve for (N)

Galina-37 [17]

Answer:

N=R/P−C/P

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable

5 0

3 years ago

What is an equation of the line that passes through the points (-6, 5) and (6, 7)?

e-lub [12.9K]

Answer:

$y=\frac{1}{6}x+6$

Step-by-step explanation:

Let $(x_1,y_1)\rightarrow(-6,5)$ and $(x_2,y_2)\rightarrow(6,7)$

<u>Determine slope</u>

<u /> $m=\frac{y_2-y_1}{x_2-x_1}\\ \\m=\frac{7-5}{6-(-6)}\\ \\m=\frac{2}{6+6}\\ \\m=\frac{2}{12}\\ \\m=\frac{1}{6}$

<u>Use either ordered pair to find the y-intercept</u>

<u /> $y=mx+b\\\\7=\frac{1}{6}(6)+b\\\\7=1+b\\\\6=b$

<u>Final equation</u>

<u /> $y=\frac{1}{6}x+6$

4 0

2 years ago

The angle θ1\theta_1 θ 1 theta, start subscript, 1, end subscript is located in Quadrant II\text{II} II start text, I, I, end

melomori [17]

Answer:

$\dfrac{3\sqrt{13}}{11}$

Step-by-step explanation:

Given that the angle $\theta_1$ is located in Quadrant II; and

$\cos(\theta_1)=-\dfrac{2}{11}$

In Quadrant II, x is negative and y is positive.

$\cos(\theta)=\dfrac{Adjacent}{Hypotenuse},\sin(\theta)=\dfrac{Opposite}{Hypotenuse}\\$Adjacent=-2\\Hypotenuse=11\\$

To find $\sin(\theta_1)$ , we first determine the opposite angle of $\theta_1$ .

This will be done using the Pythagoras theorem.

$Hypotenuse^2=Opposite^2+Adjacent^2\\11^2=Opposite^2+(-2)^2\\Opposite^2=121-4=117\\Opposite=\sqrt{117}=3\sqrt{13}$

Therefore:

$\sin(\theta_1)=\dfrac{Opposite}{Hypotenuse}=\dfrac{3\sqrt{13}}{11}$

6 0

2 years ago

The following table shows the expressions that represent the sales of two companies:

nikdorinn [45]

Answer: Company B

Step-by-step explanation: I got it right on the test

7 0

2 years ago

Read 2 more answers