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GaryK [48]
3 years ago
12

In 2004, a pine tree was 5 3/4 ft tall. If the tree grew at an average rate of 5/6 ft per year for the next 7 years, how tall wo

uld the tree have been in 2011?? Plzz o will give you 100 points
Mathematics
1 answer:
Nady [450]3 years ago
7 0

Answer:

11 7/12 ft tall

Step-by-step explanation:

5 3/4 + (5/6*7)

139/12

11 7/12

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Equation that passes through the points (-1,0)(0,2)
Simora [160]
1. Find the slope.

2. Plug the slope you found in step 1, one of the given points, and plug both into the point-slope formula.

The point-slope formula is:

y - y_1 = m(x - x_1)

3. Solve the point-slope formula for y.

Your final answer must be in the form

y = mx + b
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2 years ago
Hi I hope you are all okay could someone help me with this math question thankyou !!!
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5 0
2 years ago
Read 2 more answers
During the lunar cycle, the Moon always appears: A. to wax, but not wane. B. to wane, but not wax. C. to wax, then wane. D. to w
JulijaS [17]

Answer:

C.to wax then wane

Step-by-step explanation:

Waxing is "Maxing," or growing with light until a full moon is reached. Waning is the opposite, or decreasing after a full moon, and is always illuminated on the left. Then, there is a waxing or waning Gibbous moon, which means more than half of the moon is illuminated.

5 0
3 years ago
What is the negative reciprocal of 7/3?
-BARSIC- [3]

Answer:

-3/7

Step-by-step explanation:

Negative reciprocal means to put a negative and sign and change the numerator and denominator to be in opposite places.

7/3 -> -3/7

Best of Luck!

8 0
2 years ago
Read 2 more answers
Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol
aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

P(A\cap B)=P(A)\times P(B)

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0
3 years ago
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