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djyliett [7]
3 years ago
10

practice counting in 2's , 5's and 10's, starting on 0. whats patterns do you notice ? can you write sentences to explain these

? E.g. I notivce that all the multiples of 5 end with ____ and ____. HOMEWORK
Mathematics
1 answer:
Mice21 [21]3 years ago
7 0
When you multiply 5 by 1 you get 5. When you multiply 5 by 2 you get 10. If you keep doing this, you get a list of multiples of 5.

5
10
15
20
25
30
35
40
45
50

All of these numbers end in either 5 or 0. We can do the same with 2's and 10's.

2
4
6
8
10
12
14
16
18
20

For all 2's we can see that they are all even and end with an even number (0,2,4,6,8)

10
20
30
40
50
60
70
80
90
100

For 10's we can see that they all end in 0.
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Answer:  \bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, B=\dfrac{6}{5}  →   P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}

Half of that period is: \dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}

Calculate the period for each of the options to find a match:

A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}

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