Answer:
3/8 of a book per week
Step-by-step explanation:
Answer:
the answer is $200
Step-by-step explanation:
i am taking the khan academy quiz right now
Solve:
"<span>twice the number minus three times the reciprocal of the number is equal to 1."
3(1)
Let the number be n. Then 2n - ------- = 1
n
Mult all 3 terms by n to elim. the fractions:
2n^2 - 3 = n. Rearranging this, we get 2n^2 - n - 3 = 0.
We need to find the roots (zeros or solutions) of this quadratic equation.
Here a=2, b= -1 and c= -3. Let's find the discriminant b^2-4ac first:
disc. = (-1)^2 - 4(2)(-3) = 1 + 24 = 25.
That's good, because 25 is a perfect square.
-(-1) plus or minus 5 1 plus or minus 5
Then x = ------------------------------ = --------------------------
2(2) 4
x could be 6/4 = 3/2, or -5/4.
You must check both answers in the original equation. If the equation is true for one or the other or for both, then you have found one or more solutions.</span>
Answer:
It's not specific enough, I'll come back to you!
Your sequence
-8, 16/3, -32/9, 64/27
is a geometric sequence with first term -8 and common ratio
(16/3)/(-8) = (-32/9)/(16/3) = -2/3
The general term an of a geometric sequence with first term a1 and ratio r is given by
an = a1·r^(n-1)
For your sequence, this is
an = -8·(-2/3)^(n-1)
