It is C (the one on the bottom left) because none of the X-values are used twice. On all the others their X-values are used more then once.
Answer:
The answer is B. 65
Step-by-step explanation:
add 43 and 22, then subtract that by 180 and that will give you 115. Then subtract 180 and 115 and the answer is 65.
Answer:
nothing
a point
a segment
Step-by-step explanation:
nothing
a point
a segment
Answer:
Step-by-step explanation:
If we take out the extra $3, we can group the bills into one each of $5 and $1, for a value of $6. There will be 7 such groups in the remaining $42.
That means there are 7 bills of the $5 denomination, and 3 more than that (10 bills) of the $1 denomination.
There are 7 $5 bills and 10 $1 bills.
_____
If you want to write an equation, it is usually best to let a variable stand for the most-valuable contributor. Here, we can let x represent then number of $5 bills. Then the value of the cash box is ...
5x +(x+3) = 45
6x = 42 . . . . . . . . subtract 3, collect terms
x = 7 . . . . . . . . . . . there are 7 $5 bills
x+3 = 10 . . . . . . . . there are 10 $1 bills
You may notice that this working parallels the verbal description above. (After we subtract $3, x is the number of $6 groups.)
We have been given an equation of circle 
. We are asked to find the center and radius of the circle.
First of all, we will write equation of circle is standard form 
, where center of circle is at point (h,k) and radius is r.
Let us complete the square for both x and y.
Adding half the square of coefficient of x and y term, we will get:
Therefore, the center of the circle is 
and radius is 4 units.
