C. The functions fans g have different axes of symmetry and different minimum values
Given:
The number of checkers is 12.
The number of red is 5/6 times of 12.
Multiply 5/6 and 12 to find the number of red.
Hence there are 10 red in checkers.
Let event A = Caroline buys fruit, event B = Caroline buys CD, Ac and Bc are complementary events.
Events AB, ABc, AcB and AcBc are jointly exhaustive and disjoint, hence P(AB) + P(ABc) + P(AcB) +P(AcBc) =1.
Events A and B independent, hence Ac and Bc independent too and probability P(AcBc) = P(Ac)*P(Bc) = (1 - P(A))(1-P(B)) = 0.6*0.4 = 0.24.
Required probability P(AB + ABc + AcB ) = P(AB) + P(ABc) + P(AcB) = 1- P(AcBc) = 1 - 0.24 = 0.76.
Answer: Probability that Caroline buys fruit, a CD or both is 0.76.
The answer is 11x11x11=1331
