2 years ago

Find 63% of 77. a. 0.485 b. 48.5 c.0.818 d.81.8

Mathematics

1 answer:

8_murik_8 [283]2 years ago

8 0

Answer:

b) 48.5

Step-by-step explanation:

63%= 0.63*77= 48.5

You might be interested in

Solve the following equation, answer as a reduced, mixed number. Then place the correct number in the box provided. 4(3 - 2x) =

valentinak56 [21]

Answer:

x = -3/8

Step-by-step explanation:

4(3 - 2x) = 15

Distribute

12 -8x = 15

Subtract 12 from each side

12-8x-12 =15-12

-8x =3

Divide by -8

-8x/-8 = 3/-8

x = -3/8

8 0

3 years ago

Read 2 more answers

Evaluate the expression for x= 2 and y=4. Enter your answer in the box. 16x + 2x2 - y2

Nostrana [21]

Answer:

Step-by-step explanation:

Step 1: Define

x = 2

y = 4

16x + 2x² - y²

Step 2: Substitute and Evaluate

16(2) + 2(2)² - 4²

32 + 2(4) - 16

16 + 8

8 0

3 years ago

Can anyone help me with this math test heres another question on it!!

stira [4]

Answer:

31 1/2, or answer D

Step-by-step explanation:

Because you have three countertops which all have an area of 10 1/2 meaning you multiply 10.5x3 getting 31.5

8 0

2 years ago

1. Professor Cramer determines a final grade based on attendance, two papers, three major tests, and a final exam. Each of these

ELEN [110]

Answer:

Ur final grade will go down if you are looking for answers buddy! :)

Step-by-step explanation:

5 0

2 years ago

An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes. The results wer

liraira [26]

Step-by-step explanation:

since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

$\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1$

So probabaility for $\mathrm{X}=1$ is

$P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679$

So expected frequency for $X=1$ is $0.3679^{*} 30=11.037$ (or $\left.11.04\right)$ .

8 0

2 years ago