0=44-25t-5t^2
t^2+2t-8=0
(t+4)(t-2)=0
t=-4 (not a solution) or t=2
Answer: after 2 seconds
25c - 5
Simplify all of the answer choices & see which one is correct.
a) 5(5c - 1)
25c - 5
A) IS CORRECT.
b) 5(20c + 1)
100c + 5
B IS INCORRECT.
c) 5(5c)
25c
C IS INCORRECT.
d) 5(c -1 )
5c - 5
D IS INCORRECT.
Therefore, the correct answer is a) 5(5c - 1)
~Hope I helped!~
Answer:
b
Step-by-step explanation:
you can use trial and error to solve this btw that's what I used and once I got to answer choice b, i plugged in the 2 numbers into the equation based of of their axis once i did that the equation now looked like this 9=3+3, when you solve this the equation would then look like this 9=6 and we both know that 9 doesn't not equal 6 so that is your answer.
F(x+h) = 2(x+h) +3= 2x + 2h +3
f(x) = 2x + 5
f(x+h) - f(x) = 2x + 2h + 3- 2x - 3= 2h
[f(x+h) - f(x)]/h = 2h/h = 2
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)
The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)
Answer: The system of inequalities would produce the region indicated on the graph is Option B
