Determine the area for the diagram above plzzzzz

Mathematics

2 answers:

gulaghasi [49]3 years ago

4 0

Answer:

see explanation

Step-by-step explanation:

The figure shown has one pair of parallel sides and is a trapezium

The area (A) of a trapezium is calculated using

A = $\frac{1}{2}$ h(a + b)

where h is the height and a, b the length of the parallel sides

here h = 2w, a = w + 3 and b = 4w - 2, hence

A = $\frac{1}{2}$ × 2w(w + 3 + 4w - 2)

= w(5w + 1) = 5w² + w

kap26 [50]3 years ago

4 0

Answer:

5w² + w

<u>Step-by-step explanation:</u>

The figure shown has one pair of parallel sides and is a trapezium

The area (A) of a trapezium is calculated using

A = h(a + b)

where h is the height and a, b the length of the parallel sides

here h = 2w, a = w + 3 and b = 4w - 2, hence

A = × 2w(w + 3 + 4w - 2)

= w(5w + 1) = 5w² + w

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3 years ago

Read 2 more answers

LAST ONE GUYSSS \small \angle L and \small \angle M are supplementary, \small m\angle L=12x+45 and \small m\angle M=18x-30. Dete

svp [43]

Answer:

$m\angle L = 111\degree \\m\angle M = 69\degree$

Step-by-step explanation:

Since, angle L and angle M are supplementary.

$\therefore m\angle L + m\angle M= 180\degree \\ \therefore \: 12x + 45 + 18x - 30 = 180 \degree \\ \therefore \: 30x + 15= 180 \degree\\ \therefore \: 30x= 180 \degree - 15 \degree\\ \therefore \: 30x= 165 \degree \\ x = \frac{165 \degree}{30} \\ x = 5.5 \degree \\ \\ m\angle L = 12x + 45 \\ m\angle L = 12 \times 5.5 + 45 \\ m\angle L = 66 + 45 \\ \huge \red{ \boxed{ m\angle L = 111 \degree}} \\ \\ m\angle M=18x - 30 \\ m\angle M=18 \times 5.5 - 30 \\ m\angle M=99 - 30 \\ \huge \purple{ \boxed{ m\angle M=69 \degree}} \\$