Determine the area for the diagram above plzzzzz
2 answers:
Answer:
see explanation
Step-by-step explanation:
The figure shown has one pair of parallel sides and is a trapezium
The area (A) of a trapezium is calculated using
A = h(a + b)
where h is the height and a, b the length of the parallel sides
here h = 2w, a = w + 3 and b = 4w - 2, hence
A = × 2w(w + 3 + 4w - 2)
= w(5w + 1) = 5w² + w
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see the attached figure
we know that
1) the graph open downward
2) the vertex of the graphic is the point (-2,5)
3) the axis of symmetry of the graph is x=-2
4) the x intercept values are (-5.873,0) and (1.873,0)
5) the y intercept value is (0,3.667)
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<span>y=-1/3(x+2)</span>²<span>+5
using a graph tool
see the attached figure
we know that
1) the graph open downward
2) the vertex of the graphic is the point (-2,5)
3) the axis of symmetry of the graph is x=-2
4) the x intercept values are (-5.873,0) and (1.873,0)
5) the y intercept value is (0,3.667)
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