Determine the area for the diagram above plzzzzz
2 answers:
Answer:
see explanation
Step-by-step explanation:
The figure shown has one pair of parallel sides and is a trapezium
The area (A) of a trapezium is calculated using
A = h(a + b)
where h is the height and a, b the length of the parallel sides
here h = 2w, a = w + 3 and b = 4w - 2, hence
A = × 2w(w + 3 + 4w - 2)
= w(5w + 1) = 5w² + w
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Answer:
- -108.26
- -108.13
- -108.052
- -108.026
- -108
Step-by-step explanation:
A graphing calculator or spreadsheet is useful for making the repeated function evaluations required.
The average velocity on the interval [a,b] will be ...
v avg = (y(b) - y(a))/(b-a)
Here, all the intervals start at a=3, so the average velocity for the given values of t will be ...
v avg = (y(3+t) -y(3))/((3+t) -3) = (y(3+t) -y(3))/t
This can be computed for each of the t-values given. The results are shown in the attached table.
__
We note that the fractional part of the velocity gets smaller in proportion to t getting smaller. We expect it to go to 0 when t goes to 0.
The estimated instantaneous velocity is -108 ft/s.
_____
We can simplify the average velocity equation to ...
v avg = ((48(3+t) -26(t+3)^2) -(48(t+3) -26(3)^2)) / t
= (48t -26(t^2 +6t))/t
= 48 -26t -156
<em> v avg = -108 -26t</em>
Then the average velocity at t=0 is -108.
