4/5y + 3(2/5x + 7/5y)...distribute thru the parenthesis
4/5y + 6/5x + 21/5y ...combine like terms
25/5y + 6/5x.....reduce
5y + 6/5x
Answer:
Step-by-step explanation:
since there are 205 calories in 5 crackers we can represent this as
205/5
we need to find how many calories are in one cracker, so lets take "x" as the # of calories in 1 cracker
so

cross multiply
5x=205
divide by 5 on both sides
x=41
41 calories in 1 cracker
Number line:
Answer:
C choice.
Step-by-step explanation:

First, we move the same terms to the same side.

Then we move 6 to divide - 18.

10g = 4/6....divide both sides by 10
g = (4/6) / 10
g = 4/6 * 1/10
g = 4/60 which reduces to 1/15 <==