Oh ok .so the answer is.....2838384764733 I suggest the method of comparing variables
Answer:
100
Step-by-step explanation:
Answer:
9:30 she finishes
Step-by-step explanation:
815 plus 75 is 890
there are 60 minutes in one hour
890-60 is 830
add 100 to represent another Hour
830 plus 100 is 930
9:30
therefore, it is 9:30
50
64=1, 2, 4, 8, 16, 32, 64
80
Answer:
<em>There are approximately 114 rabbits in the year 10</em>
Step-by-step explanation:
<u>Exponential Growth
</u>
The natural growth of some magnitudes can be modeled by the equation:

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.
We are given two measurements of the population of rabbits on an island.
In year 1, there are 50 rabbits. This is the point (1,50)
In year 5, there are 72 rabbits. This is the point (5,72)
Substituting in the general model, we have:

![50=P_o(1+r)\qquad\qquad[1]](https://tex.z-dn.net/?f=50%3DP_o%281%2Br%29%5Cqquad%5Cqquad%5B1%5D)
![72=P_o(1+r)^5\qquad\qquad[2]](https://tex.z-dn.net/?f=72%3DP_o%281%2Br%29%5E5%5Cqquad%5Cqquad%5B2%5D)
Dividing [2] by [1]:

Solving for r:
![\displaystyle r=\sqrt[4]{\frac{72}{50}}-1](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B72%7D%7B50%7D%7D-1)
Calculating:
r=0.095445
From [1], solve for Po:



The model can be written now as:

In year t=10, the population of rabbits is:

P = 113.6

There are approximately 114 rabbits in the year 10