Answer:
<CFD =62°
<AFB= 90°
Step-by-step explanation:
here you have a vertical angle, so to simply put it the answer on one side of the angle is the same answer for the opposite side of the angle. knowing this, angle <AFE is 62° and <CFD is on the opposite side making the angle the same(62°). the opposite angle of <AFB is <EFD which is 118° but both <AFB and <AFC equal 118° so you subtract 118° to <AFC degree which is 28° and you get 90°.
i hope this makes sense im not good at explaining. if anyone has a better explanation feel free to correct me.
How many points will you give?
Answer:
a= 4.993
c = 5.824
A= 59°
C = 90°
Step-by-step explanation:
b=3, B=31°
Since it's a right angle.
C = 90°
A = 180-90-31
A= 59°
For side a and c
a/sin A = b /sin B
a = sinA * b/sin B
a= sin 59 * 3/sin31
a= 4.993
a = 5
c/sin C = b/sin B
c = sin C * b/sin B
c = sin90 * 3/sin 31
c = 1* 5.824
c = 5.824
Check the slope between the moving points
<span>slope between (–6, –1) & (–3, 2) = 1 </span>
<span>slope between (-3, 2) & (–1, 4) = 1 </span>
<span>slope between (-1, 4) & (2, 7) = 1 </span>
<span>the points are collinear and make an angle of 45 degrees with the x-axis </span>
<span>we can have an equation of a line passing through (-6,-1) and slope 1 as </span>
<span>(y + 1) = 1(x + 6) </span>
<span>y = x + 5 is your linear model mostly</span>
The interquartile range (IQR) is 15.
To find the IQR, you must:
1) Find the median
2) Split the data set in two at the median.
3) Find the medians from both the groups you made in Step 2
4) Label the smaller one Quartile 1 and the larger one Quartile 3 (Hint: The median is Quartile 2)
5) Subtract: Quartile 3 - Quartile 1
