25% of what number is 20

True or False? A circle could be circumscribed about the quadrilateral below.

KengaRu [80]

The answer is false your welcome

6 0

3 years ago

Christina's purchasing a new TV. She was approved to finance the TV with zero interest. If Christina gives a one-time payment of

Allisa [31]

Given:

One time payment, p = $300

Payment per month, q = $65

Number of months paid, n = 5

The objectiv is to find the amount she paid in 5 months.

Let x be the amount she paid in 5 months. Then the the formula is,

$x=p+nq$

Let's substitute the values.

$\begin{gathered} x=300+5(65) \\ x=300+325 \\ x=625 \end{gathered}$

Hence, total amount paid in 5 months is $625.

3 0

1 year ago

How do i divide decimals by whole numbers

Vinvika [58]

You should check out Kahn academy

4 0

3 years ago

Write a polynomial as the sum of the monomials and write it in standard form. For each of the above specify the degree of the re

klio [65]

Answer:

2b³ +2a -2c . . . . degree 3 polynomial

Step-by-step explanation:

The monomials are ...

... 4a . . . . degree 1 in a

... -5b·b² = -5b³ . . . . degree 3 in b

... -3c . . . . degree 1 in c

... 7b³ . . . . degee 3 in b (like term with -5b³)

... +c . . . . degree 1 in c (like term with -3c)

... -2a . . . . degree 1 in a (like term with 4a)

So, we have 3 pairs of like terms. The like terms can be combined by summing their coefficients.

The degree of the polynomial is that of the highest-degree term. (Here, the b³ term makes it a polynomial of degree 3.)

... 4a -2a = (4-2)a = 2a . . . . combining the "a" terms

... -5b³ +7b³ = (-5+7)b³ = 2b³ . . . . combining the b³ terms

... -3c +c = (-3 +1)c = -2c . . . . combining the "c" terms

In standard form, we write the highest-degree term first. Follwing terms are in order by decreasing degree. It is convenient, but perhaps not required, to then write the terms of the same degree in alphabetical order.

... = 2b³ +2a -2c . . . . a 3rd degree polynomial

7 0

3 years ago

Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal poi

Ksivusya [100]

Given:

A line segment with initial point (–5, 3) and terminal point (1, –6).

To find:

The set of parametric equations over the interval 0 ≤ t ≤ 1 which defines the given line segment.

Solution:

Initial point is (–5, 3). So,

$x(0)=-5,y(0)=3$

Terminal point is (1, –6).

$x(1)=1,y(1)=-6$

Check which of the given set of parametric equations satisfy $x(0)=-5,y(0)=3,x(1)=1,y(1)=-6$ .

Put t=1 in each set of parametric equations.

In option A,

$y(1)=3-6(1)=3-6=-3\neq -6$

So, option A is incorrect.

In option B,

$y(1)=1-6(1)=1-6=-5\neq -6$

So, option B is incorrect.

In option C,

$y(1)=3-9(1)=3-9=-6$

$x(1)=-5+6(1)=-5+6=1$

Put t=0, in this set of parametric equations.

$x(0)=-5+6(0)=-5$

$y(0)=3-9(0)=3$

So, option C is correct.

In option D,

$y(1)=1-7(1)=1-7=-3\neq -6$

$x(1)=-5+8(1)=-5+8=3\neq 1$

So, option D is incorrect.

8 0

3 years ago

25% of what number is 20￼

25% of what number is 20