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alexandr1967 [171]
3 years ago
10

Please help me!!!!!!! It's very important!!!!

Mathematics
1 answer:
qwelly [4]3 years ago
6 0
You could just use 3.14 or 22/7
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Find the circumference of a circle whose.<br> A. Diameter is 14cm<br> B. Radius is 3.5cm
Nikitich [7]

Hello!

Circumference of a Circle

C=πd

or

C=2πr

Plug in the values

C=14π

C≈44 cm

C=2π×3.5

C≈22 cm

Hope everything is clear.

Let me know if you have any questions!
#KeepLearning

;-)

5 0
3 years ago
What is the measure for the following ∠?<br> m∠EOD<br><br> 20<br> 120<br> 140
Eddi Din [679]

Answer:

Part 1) m∠EOD=20°

Part 2) m∠AOD=80°

Step-by-step explanation:

Part 1) Find the measure of angle EOD

we know that  °

m∠EOD=m∠EOX-m∠DOX

we have

Observing the figure

m∠EOX=140°

m∠DOX=120°

substitute

m∠EOD=140°-120°=20°

Part 2) Find the measure of angle AOD

we know that  °

m∠AOD=m∠DOX-m∠AOX

we have

Observing the figure

m∠AOX=40°

m∠DOX=120°

substitute

m∠AOD=120°-40°=80°

8 0
3 years ago
Sebastian swam laps every day in the community swimming pool. He swam 45 minutes each day, 5 days each week, for 12 weeks. In th
lord [1]

Answer:

\text{Average rate}=\frac{\text{40 laps}}{\text{ hour}}

Step-by-step explanation:

Please consider the complete question.

Sebastian swan laps every day in the community swimming pool. He swam 45 minutes each day, 5 days each week, for 12 weeks. In that time, he swam 1800 laps. What was his average rate in laps per hour?    

Let us convert time taken into hours as:

\text{Days}=5\times 12=60

\text{Minutes}=60\times 45

1 hour = 60 minutes. To convert minutes into hours, we will divide total minutes by 60.

\text{Hours}=\frac{60\times 45}{60}=45

Now, we will divide 1800 by 45 to find average rate in laps per hour as:

\text{Average rate}=\frac{\text{1800 laps}}{\text{45 hours}}

\text{Average rate}=\frac{\text{40 laps}}{\text{ hour}}

Therefore, Sebastian's average rate is 40 laps per hour.

6 0
3 years ago
Is 8 quarts equal to 32 gallons
Fittoniya [83]

Answer:

no

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The sum of the squares of two consecutive negative integers is 61. Find the smaller of the two integers
Marysya12 [62]
x^2+(x+1)^2=61\\ x^2+x^2+2x+1-61=0\\ 2x^2+2x-60=0\ \ /:2\\ x^2+x-30=0\\ \Delta=1^2-4\cdot(-40)=1+120=121\ \ \Rightarrow\ \  \sqrt{\Delta} =11\\ \\ x_1= \frac{-1-11}{2} = \frac{-12}{2} =-6,\ \ \ \ x_2= \frac{-1+11}{2} = \frac{10}{2}=5\\ \\Ans.:x=-6
3 0
4 years ago
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