The answer is (x+3)(x+5).
Once you solve for z, you will get z = -1/y + w/xy. :)
Answer:
<h2>d=(14,0)</h2>
Step-by-step explanation:
<h2>√(7-(-7))^+(4/19-4/19)^</h2><h2>√(7+7)^+(0)^</h2><h2>√(14)^+0</h2><h2>= 14</h2>
Answer:
Step-by-step explanation:
OPTION C - No, because each number drawn is equally likely and independent of the others, so this set of numbers is just as likely as any other in the next drawing.
