The center-radius form<span> of the </span>circle<span> equation is in the format (x – h)</span>2<span> + (y – k)</span>2<span> = r</span>2<span>, with the center being at the point (h, k) and the radius being "r". Therefore, the center is located at point (1, -3) and is located in the fourth quadrant, last option. Hope this answers the question.</span>
When we cube root 123, we get a decimal which rounds out to 4.97. So possible side lengths would be any number greater than that.<span />
The main formula is arc RT = r x measure <span>RST
so </span>∠RST=<span>minor arc RT / r
</span>minor arc RT = 23<span>π
r= 3 cm
</span>∠RST= 23<span>π/3</span>
Answer:
the middle sequentially in a list of numbers (sorted from lowest to highest)
Step-by-step explanation:
for example, in the dataset 2, 4, 6, 8, 10, 6 would be the median because it is in the middle when sorted properly
Using the point on the graph (4, 1) solve for a
1 = a(4-3)² - 1
2 = a
