Answer: The correct option is (a) one over two.
Step-by-step explanation: Given that Jack rolls a number cube twice. We are to find the probability that the sum of the 2 rolls is less than 8 given that he first roll is a 4.
A cube rolls 1, 2, 3, 4, 5 and 6. So, the sample space will be
S = {1, 2, 3, 4, 5, 6}.
That is, n(S) = 6.
Since the first roll is a 4, so the options for the second roll are 1, 2 and 3 so that the sum is less than 8.
Therefore, if 'A' is the event that the sum is less than 4, then
A = {1, 2, 3}.
That is, n(A) = 3.
So, the probability of happening of event A is given by
![P(A)=\dfrac{n(A)}{n(S)}=\dfrac{3}{6}=\dfrac{1}{2}.](https://tex.z-dn.net/?f=P%28A%29%3D%5Cdfrac%7Bn%28A%29%7D%7Bn%28S%29%7D%3D%5Cdfrac%7B3%7D%7B6%7D%3D%5Cdfrac%7B1%7D%7B2%7D.)
Thus, the required probability is one over half.
Option (a) is correct.