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adelina 88 [10]
3 years ago
13

You are considering a 5/1 ARM. What does the 5 represent?

Mathematics
2 answers:
umka21 [38]3 years ago
7 0
The 5 is the number of years that the interest rate is fixed (at the initial amount set when you sign the mortgage contract)

The 1 represents the idea that the interest rate will change every year after the initial 5 years are up.
Nuetrik [128]3 years ago
3 0
The 5 represents the number of years that a fixed interest rate will be applied to the loan. APEX Financial literacy
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Please Subtract the Following Fractions.
vovangra [49]

¡Hola!

Your answer to the question is 10/12.

Step-by-step explanation:

By using the y^2-y^1/x^2-x^1

12-2= 10

16-4= 12

So your answer is 10/12.

Hope this Helps!

4 0
3 years ago
How do you solve n - 8 > 5
sergiy2304 [10]

n > 13

Step-by-step explanation:

n-8> 5=

Add 8 to both sides.

n > 5 + 8

Add 5 and 8 to get 13.

<u>n > 13</u>

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

Please mark as brainliest

6 0
2 years ago
Read 2 more answers
The diagram below shows a sign that Annie designed. It is made of two circles that share the same center. Annie wants to use str
Pavel [41]

132 in

Step-by-step explanation:

  • Take the total radius = 18+3 = 21= R (say)
  • Simply use the formula for the circumference i.e. 2*pi*R
  • 2*22/7*21= 132
3 0
2 years ago
Help me with (d)(ii).<br><br> Thank you!
lord [1]
q=\frac{h^{2}-k^{2}}{3m}
Cross-multiplying and rearranging, we get:
k^{2}=h^{2}-3mq
or written without using latex:
k^2 = h^2 - 3mq
Can you finish now?
4 0
3 years ago
See question in attached photo.​
statuscvo [17]

9514 1404 393

Answer:

  (a, b) = (-2, -1)

Step-by-step explanation:

The transpose of the given matrix is ...

  A^T=\left[\begin{array}{ccc}1&2&a\\2&1&2\\2&-2&b\end{array}\right]

Then the [3,1] term of the product is ...

  (A\cdot A^T)_{31}=\left[\begin{array}{ccc}a&2&b\end{array}\right]\cdot\left[\begin{array}{ccc}1&2&2\end{array}\right]=a+2b+4

and the [3,2] term is ...

  (A\cdot A^T)_{32}=\left[\begin{array}{ccc}a&2&b\end{array}\right]\cdot\left[\begin{array}{ccc}2&1&-2\end{array}\right]=2a-2b+2

Both of these terms in the product matrix are 0. We can solve the system of equations by adding these two terms:

  (a +2b +4) +(2a -2b +2) = (0) +(0)

  3a +6 = 0

  a = -2

Substituting for 'a' in term [3,1] gives ...

  -2 +2b +4 = 0

  b = -1

The ordered pair (a, b) is (-2, -1).

8 0
3 years ago
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