Solve each of the quadratic equations 3x=0.5x2

A store is offering 40% off regular priced items. The amount of discount on an item is $6, What is the regular price of this ite

mote1985 [20]

The answer would be $15

All you need to do is multiply each one by .4 and see which one equals 6.

15 x .4 =6

Hope this helps!

6 0

2 years ago

Read 2 more answers

Trigonometry answer need

Sladkaya [172]

That is the answer..............

3 0

3 years ago

Select all numbers that have an absolute value of 0.6<br> -60<br> 1/6<br> -0.6<br> 0.6

Rus_ich [418]

Answer:

60 and 0.6

Step-by-step explanation:

6 0

3 years ago

Compare the dimensions of the prisms. How many times greater is the surface area of the green prism than the surface area of the

vodomira [7]

Answer:

the green prisim is 5.59 or 5 times bigger!

Step-by-step explanation:

The surface area of the green prisim is 850 and the surface area of the blue one is 150 and 850 divided by 150 is 5.59!

5 0

3 years ago

The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What

Simora [160]

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .