You have at most 30 games on your smart phone. write an inequality that represents this situation.

A sequence of numbers is formed by the iterative process Xn+1 = (Xn )2 – Xn

xeze [42]

Step-by-step explanation:

X1 = 1

X2 = (X1) 2 - X1

X2 = 2 - 1

X2 = 1. implies that the second term of the sequence is 1.

3 0

2 years ago

HELP ME ASAP LAST PROBLEM

igomit [66]

The rate of change is -2 :)

5 0

2 years ago

Read 2 more answers

Find the area of a circle with a

lina2011 [118]

Answer:

254.34 in.²

Step-by-step explanation:

area = πr²

given, radius = 9 cm

according to formula

→ 3.14 × (9)²

→ 3.14 × 81

→ 254.34 in.² ans.

hope this helps you !

6 0

2 years ago

If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)] 2. 1 2 9

arsen [322]

Put the argument value where the variable is, then evaluate.
For f(x), you want f(2).
f(2) = 2² + 1 = 4+1 = 5

For g(x), you want g(1).
g(1) = 3·1 +1 = 4

For [f(2) - g(1)] you want the difference of the above values.
[f(2) - g(1)] = [5 - 4] = 1

8 0

3 years ago

Thirty percent of all customers who enter a department store will make a purchase. Suppose that 6 customers enter the store and

torisob [31]

Answer:

Step-by-step explanation:

Let's use binomial distribution, because we are interested in find the total number of successes in a sequence of n independent experiments.

In probability, a binomial distribution is used in a Bernoulli process. That is, a sequence of experiments of n independent trials, each asking a dichotomous question, that means it only has two answers. One answer is a success (probability: p) and the other is a failure (probability: 1-p). In this case, every customer who enters in the store is the experiment. If they make a purchase is a success event, taking into account that every purchase decision has to be independent.

$P(X=x) = C(n,x)p^{x} (1-p)^{n-x}$

x= total number of success

n= total number of experiments

p=probability of success on an indivual trial

$C(n,x) = \frac{n!}{x!(n-x)!}$

a) x= 5 ------> customers that make a purchase

n= 6 ------> total customers

p=0.3

$p(X=5)= C(6,5)(0.3)^{5} (1-0.3)^{6-5} \\p(X=5)=0.102$

b) At least 3 customers make a purchase. x ≥ 3

$P(X\geq 3)=1-P (X=0)-P(X=1)-P(X=2)\\P(X\geq 3)=1-(C(6,0)(0.3^{0})(0.7)^{6}) - (C(6,1)(0.3^{1})(0.7)^{5}) - (C(6,2)(0.3^{2})(0.7)^{4})\\ P(X\geq 3) = 1-0.11765-0.30253-0.32414\\P(X\geq3)= 0.2557$

c) At most 2 customers make a purchase. x ≤ 2

$P(X\leq2) = P(X=0) + P(X=1) + P(X=2)\\P(X\leq2) = (C(6,0)(0.3^{0})(0.7)^{6}) + (C(6,1)(0.3^{1})(0.7)^{5}) + (C(6,2)(0.3^{2})(0.7)^{4})\\P(X\leq2) = 0.11765-0.30253-0.32414\\P(X\leq2)=0.7443$

d)At least 1 customer makes a purchase. x ≥ 1

$P(X\geq 1)=1-P(X=0)\\P(X\geq 1)= 1-C(0,6)(0.3)^{0}(0.7)^{6} \\P(X\geq 1)= 1-0.11765 = 0.8824$

e)They must be kind to customers, always willing to help and give information about products clearly and honestly.

Have enough inventory and offer promotions for the purchase of more than one product

Have an agile payment system that avoids rows and delays in purchases.

6 0

3 years ago